Apply MapThread to all but one variableHow do you efficiently return all of a List but one element?All values for a function with two arguments without OuterEfficiently finding the maximum value of a column in a matrixnested use of Apply/Map/MapThread in pure functionsMapThread AlternativesFinding neighbors from listMapThread problemapply binary operation to all adjacent pairsFlip sign of one variable in listFind numbers from Mean, Variance and Correlation coefficient
How do I check if a string is entirely made of the same substring?
Don’t seats that recline flat defeat the purpose of having seatbelts?
How does Captain America channel this power?
How to denote matrix elements succinctly?
What is the smallest unit of eos?
"You've called the wrong number" or "You called the wrong number"
How to fry ground beef so it is well-browned
On The Origin of Dissonant Chords
Aligning equation numbers vertically
Is it idiomatic to construct against `this`
a sore throat vs a strep throat vs strep throat
A Note on N!
Do I have an "anti-research" personality?
What happened to Captain America in Endgame?
Are there physical dangers to preparing a prepared piano?
Is the claim "Employers won't employ people with no 'social media presence'" realistic?
Mistake in years of experience in resume?
Betweenness centrality formula
Alignment of various blocks in tikz
What's the polite way to say "I need to urinate"?
How do I deal with a coworker that keeps asking to make small superficial changes to a report, and it is seriously triggering my anxiety?
How could Tony Stark make this in Endgame?
Dynamic SOQL query relationship with field visibility for Users
Is there a way to generate a list of distinct numbers such that no two subsets ever have an equal sum?
Apply MapThread to all but one variable
How do you efficiently return all of a List but one element?All values for a function with two arguments without OuterEfficiently finding the maximum value of a column in a matrixnested use of Apply/Map/MapThread in pure functionsMapThread AlternativesFinding neighbors from listMapThread problemapply binary operation to all adjacent pairsFlip sign of one variable in listFind numbers from Mean, Variance and Correlation coefficient
$begingroup$
I would like to know what is the most efficient to implement the following computation. Given three lists
a = a_1,a_2, a_3, …, a_n
b = b_1,b_2, b_3, …, b_n
c = c_1,c_2, c_3, …, c_n
and a function $f(x_1,x_2,x_3)$, obtain
f(a_1,b_1,c_1) f(a_1,b_1,c_2) ..... f(a_1,b_1,c_n)
f(a_2,b_2,c_1) f(a_2,b_2,c_2) ..... f(a_2,b_2,c_n)
..... ..... ..... .....
f(a_n,b_n,c_1) f(a_n,b_n,c_2) ..... f(a_n,b_n,c_n)
I cannot find a solution not using For.
list-manipulation
edited 2 hours ago
corey979
20.9k64382
asked 2 hours ago
SmerdjakovSmerdjakov
1305
$endgroup$
add a comment |
$begingroup$
I would like to know what is the most efficient to implement the following computation. Given three lists
a = a_1,a_2, a_3, …, a_n
b = b_1,b_2, b_3, …, b_n
c = c_1,c_2, c_3, …, c_n
and a function $f(x_1,x_2,x_3)$, obtain
f(a_1,b_1,c_1) f(a_1,b_1,c_2) ..... f(a_1,b_1,c_n)
f(a_2,b_2,c_1) f(a_2,b_2,c_2) ..... f(a_2,b_2,c_n)
..... ..... ..... .....
f(a_n,b_n,c_1) f(a_n,b_n,c_2) ..... f(a_n,b_n,c_n)
I cannot find a solution not using For.
list-manipulation
edited 2 hours ago
corey979
20.9k64382
asked 2 hours ago
SmerdjakovSmerdjakov
1305
$endgroup$
add a comment |
$begingroup$
I would like to know what is the most efficient to implement the following computation. Given three lists
a = a_1,a_2, a_3, …, a_n
b = b_1,b_2, b_3, …, b_n
c = c_1,c_2, c_3, …, c_n
and a function $f(x_1,x_2,x_3)$, obtain
f(a_1,b_1,c_1) f(a_1,b_1,c_2) ..... f(a_1,b_1,c_n)
f(a_2,b_2,c_1) f(a_2,b_2,c_2) ..... f(a_2,b_2,c_n)
..... ..... ..... .....
f(a_n,b_n,c_1) f(a_n,b_n,c_2) ..... f(a_n,b_n,c_n)
I cannot find a solution not using For.
list-manipulation
edited 2 hours ago
corey979
20.9k64382
asked 2 hours ago
SmerdjakovSmerdjakov
1305
$endgroup$
I would like to know what is the most efficient to implement the following computation. Given three lists
a = a_1,a_2, a_3, …, a_n
b = b_1,b_2, b_3, …, b_n
c = c_1,c_2, c_3, …, c_n
and a function $f(x_1,x_2,x_3)$, obtain
f(a_1,b_1,c_1) f(a_1,b_1,c_2) ..... f(a_1,b_1,c_n)
f(a_2,b_2,c_1) f(a_2,b_2,c_2) ..... f(a_2,b_2,c_n)
..... ..... ..... .....
f(a_n,b_n,c_1) f(a_n,b_n,c_2) ..... f(a_n,b_n,c_n)
I cannot find a solution not using For.
list-manipulation
list-manipulation
edited 2 hours ago
corey979
20.9k64382
asked 2 hours ago
SmerdjakovSmerdjakov
1305
edited 2 hours ago
corey979
20.9k64382
asked 2 hours ago
SmerdjakovSmerdjakov
1305
edited 2 hours ago
corey979
20.9k64382
edited 2 hours ago
corey979
20.9k64382
edited 2 hours ago
corey979
20.9k64382
20.9k64382
asked 2 hours ago
SmerdjakovSmerdjakov
1305
asked 2 hours ago
SmerdjakovSmerdjakov
1305
asked 2 hours ago
SmerdjakovSmerdjakov
1305
1305
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
Here's one way to do it with Outer:
n = 3;
l1 = Array[a, n];
l2 = Array[b, n];
l3 = Array[c, n];
Outer[
f[#1[[1]], #1[[2]], #2] &,
Transpose @ l1, l2,
l3,
1
]
Out[25]= f[a[1], b[1], c[1]], f[a[1], b[1], c[2]],
f[a[1], b[1], c[3]], f[a[2], b[2], c[1]], f[a[2], b[2], c[2]],
f[a[2], b[2], c[3]], f[a[3], b[3], c[1]], f[a[3], b[3], c[2]],
f[a[3], b[3], c[3]]
answered 2 hours ago
Sjoerd SmitSjoerd Smit
4,610817
$endgroup$
1
$begingroup$
OrOuter[f[Sequence @@ #1, #2] &, Transpose@l1, l2, l3, 1]so you don't need to unravel#1manually.
$endgroup$
– Roman
2 hours ago
add a comment |
$begingroup$
a = a1, a2, a3, a4, a5;
b = b1, b2, b3, b4, b5;
c = c1, c2, c3, c4, c5;
Table[f[a[[j]], b[[j]], c[[k]]], j, 1, 5, k, 1, 5]
answered 2 hours ago
corey979corey979
20.9k64382
$endgroup$
add a comment |
$begingroup$
Another possibility is to use the 3-arg version of Thread. With Sjoerd's example:
n = 3;
l1 = Array[a,n];
l2 = Array[b,n];
l3 = Array[c,n];
Using Thread:
Thread /@ Thread[f[l1, l2, l3], List, 2]
f[a[1], b[1], c[1]], f[a[1], b[1], c[2]],
f[a[1], b[1], c[3]], f[a[2], b[2], c[1]], f[a[2], b[2], c[2]],
f[a[2], b[2], c[3]], f[a[3], b[3], c[1]], f[a[3], b[3], c[2]],
f[a[3], b[3], c[3]]
answered 1 hour ago
Carl WollCarl Woll
75.9k3100198
$endgroup$
add a comment |
Your Answer
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "387"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f197144%2fapply-mapthread-to-all-but-one-variable%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Here's one way to do it with Outer:
n = 3;
l1 = Array[a, n];
l2 = Array[b, n];
l3 = Array[c, n];
Outer[
f[#1[[1]], #1[[2]], #2] &,
Transpose @ l1, l2,
l3,
1
]
Out[25]= f[a[1], b[1], c[1]], f[a[1], b[1], c[2]],
f[a[1], b[1], c[3]], f[a[2], b[2], c[1]], f[a[2], b[2], c[2]],
f[a[2], b[2], c[3]], f[a[3], b[3], c[1]], f[a[3], b[3], c[2]],
f[a[3], b[3], c[3]]
answered 2 hours ago
Sjoerd SmitSjoerd Smit
4,610817
$endgroup$
1
$begingroup$
OrOuter[f[Sequence @@ #1, #2] &, Transpose@l1, l2, l3, 1]so you don't need to unravel#1manually.
$endgroup$
– Roman
2 hours ago
add a comment |
$begingroup$
Here's one way to do it with Outer:
n = 3;
l1 = Array[a, n];
l2 = Array[b, n];
l3 = Array[c, n];
Outer[
f[#1[[1]], #1[[2]], #2] &,
Transpose @ l1, l2,
l3,
1
]
Out[25]= f[a[1], b[1], c[1]], f[a[1], b[1], c[2]],
f[a[1], b[1], c[3]], f[a[2], b[2], c[1]], f[a[2], b[2], c[2]],
f[a[2], b[2], c[3]], f[a[3], b[3], c[1]], f[a[3], b[3], c[2]],
f[a[3], b[3], c[3]]
answered 2 hours ago
Sjoerd SmitSjoerd Smit
4,610817
$endgroup$
1
$begingroup$
OrOuter[f[Sequence @@ #1, #2] &, Transpose@l1, l2, l3, 1]so you don't need to unravel#1manually.
$endgroup$
– Roman
2 hours ago
add a comment |
$begingroup$
Here's one way to do it with Outer:
n = 3;
l1 = Array[a, n];
l2 = Array[b, n];
l3 = Array[c, n];
Outer[
f[#1[[1]], #1[[2]], #2] &,
Transpose @ l1, l2,
l3,
1
]
Out[25]= f[a[1], b[1], c[1]], f[a[1], b[1], c[2]],
f[a[1], b[1], c[3]], f[a[2], b[2], c[1]], f[a[2], b[2], c[2]],
f[a[2], b[2], c[3]], f[a[3], b[3], c[1]], f[a[3], b[3], c[2]],
f[a[3], b[3], c[3]]
answered 2 hours ago
Sjoerd SmitSjoerd Smit
4,610817
$endgroup$
Here's one way to do it with Outer:
n = 3;
l1 = Array[a, n];
l2 = Array[b, n];
l3 = Array[c, n];
Outer[
f[#1[[1]], #1[[2]], #2] &,
Transpose @ l1, l2,
l3,
1
]
Out[25]= f[a[1], b[1], c[1]], f[a[1], b[1], c[2]],
f[a[1], b[1], c[3]], f[a[2], b[2], c[1]], f[a[2], b[2], c[2]],
f[a[2], b[2], c[3]], f[a[3], b[3], c[1]], f[a[3], b[3], c[2]],
f[a[3], b[3], c[3]]
answered 2 hours ago
Sjoerd SmitSjoerd Smit
4,610817
answered 2 hours ago
Sjoerd SmitSjoerd Smit
4,610817
answered 2 hours ago
Sjoerd SmitSjoerd Smit
4,610817
answered 2 hours ago
Sjoerd SmitSjoerd Smit
4,610817
4,610817
1
$begingroup$
OrOuter[f[Sequence @@ #1, #2] &, Transpose@l1, l2, l3, 1]so you don't need to unravel#1manually.
$endgroup$
– Roman
2 hours ago
add a comment |
1
$begingroup$
OrOuter[f[Sequence @@ #1, #2] &, Transpose@l1, l2, l3, 1]so you don't need to unravel#1manually.
$endgroup$
– Roman
2 hours ago
1
1
$begingroup$
Or
Outer[f[Sequence @@ #1, #2] &, Transpose@l1, l2, l3, 1] so you don't need to unravel #1 manually.$endgroup$
– Roman
2 hours ago
$begingroup$
Or
Outer[f[Sequence @@ #1, #2] &, Transpose@l1, l2, l3, 1] so you don't need to unravel #1 manually.$endgroup$
– Roman
2 hours ago
add a comment |
$begingroup$
a = a1, a2, a3, a4, a5;
b = b1, b2, b3, b4, b5;
c = c1, c2, c3, c4, c5;
Table[f[a[[j]], b[[j]], c[[k]]], j, 1, 5, k, 1, 5]
answered 2 hours ago
corey979corey979
20.9k64382
$endgroup$
add a comment |
$begingroup$
a = a1, a2, a3, a4, a5;
b = b1, b2, b3, b4, b5;
c = c1, c2, c3, c4, c5;
Table[f[a[[j]], b[[j]], c[[k]]], j, 1, 5, k, 1, 5]
answered 2 hours ago
corey979corey979
20.9k64382
$endgroup$
add a comment |
$begingroup$
a = a1, a2, a3, a4, a5;
b = b1, b2, b3, b4, b5;
c = c1, c2, c3, c4, c5;
Table[f[a[[j]], b[[j]], c[[k]]], j, 1, 5, k, 1, 5]
answered 2 hours ago
corey979corey979
20.9k64382
$endgroup$
a = a1, a2, a3, a4, a5;
b = b1, b2, b3, b4, b5;
c = c1, c2, c3, c4, c5;
Table[f[a[[j]], b[[j]], c[[k]]], j, 1, 5, k, 1, 5]
answered 2 hours ago
corey979corey979
20.9k64382
answered 2 hours ago
corey979corey979
20.9k64382
answered 2 hours ago
corey979corey979
20.9k64382
answered 2 hours ago
corey979corey979
20.9k64382
20.9k64382
add a comment |
add a comment |
$begingroup$
Another possibility is to use the 3-arg version of Thread. With Sjoerd's example:
n = 3;
l1 = Array[a,n];
l2 = Array[b,n];
l3 = Array[c,n];
Using Thread:
Thread /@ Thread[f[l1, l2, l3], List, 2]
f[a[1], b[1], c[1]], f[a[1], b[1], c[2]],
f[a[1], b[1], c[3]], f[a[2], b[2], c[1]], f[a[2], b[2], c[2]],
f[a[2], b[2], c[3]], f[a[3], b[3], c[1]], f[a[3], b[3], c[2]],
f[a[3], b[3], c[3]]
answered 1 hour ago
Carl WollCarl Woll
75.9k3100198
$endgroup$
add a comment |
$begingroup$
Another possibility is to use the 3-arg version of Thread. With Sjoerd's example:
n = 3;
l1 = Array[a,n];
l2 = Array[b,n];
l3 = Array[c,n];
Using Thread:
Thread /@ Thread[f[l1, l2, l3], List, 2]
f[a[1], b[1], c[1]], f[a[1], b[1], c[2]],
f[a[1], b[1], c[3]], f[a[2], b[2], c[1]], f[a[2], b[2], c[2]],
f[a[2], b[2], c[3]], f[a[3], b[3], c[1]], f[a[3], b[3], c[2]],
f[a[3], b[3], c[3]]
answered 1 hour ago
Carl WollCarl Woll
75.9k3100198
$endgroup$
add a comment |
$begingroup$
Another possibility is to use the 3-arg version of Thread. With Sjoerd's example:
n = 3;
l1 = Array[a,n];
l2 = Array[b,n];
l3 = Array[c,n];
Using Thread:
Thread /@ Thread[f[l1, l2, l3], List, 2]
f[a[1], b[1], c[1]], f[a[1], b[1], c[2]],
f[a[1], b[1], c[3]], f[a[2], b[2], c[1]], f[a[2], b[2], c[2]],
f[a[2], b[2], c[3]], f[a[3], b[3], c[1]], f[a[3], b[3], c[2]],
f[a[3], b[3], c[3]]
answered 1 hour ago
Carl WollCarl Woll
75.9k3100198
$endgroup$
Another possibility is to use the 3-arg version of Thread. With Sjoerd's example:
n = 3;
l1 = Array[a,n];
l2 = Array[b,n];
l3 = Array[c,n];
Using Thread:
Thread /@ Thread[f[l1, l2, l3], List, 2]
f[a[1], b[1], c[1]], f[a[1], b[1], c[2]],
f[a[1], b[1], c[3]], f[a[2], b[2], c[1]], f[a[2], b[2], c[2]],
f[a[2], b[2], c[3]], f[a[3], b[3], c[1]], f[a[3], b[3], c[2]],
f[a[3], b[3], c[3]]
answered 1 hour ago
Carl WollCarl Woll
75.9k3100198
answered 1 hour ago
Carl WollCarl Woll
75.9k3100198
answered 1 hour ago
Carl WollCarl Woll
75.9k3100198
answered 1 hour ago
Carl WollCarl Woll
75.9k3100198
75.9k3100198
add a comment |
add a comment |
Thanks for contributing an answer to Mathematica Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f197144%2fapply-mapthread-to-all-but-one-variable%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
