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If I score a critical hit on an 18 or higher, what are my chances of getting a critical hit if I roll 3d20?
The 2019 Stack Overflow Developer Survey Results Are InWhat are my chances of rolling a natural 19/20 critical if I roll 3d20?What modifiers are and are not included in a DnD 3.5e critical hit?How do I roll for damage with a critical hit?Great Weapon Master Critical Hit ResolutionCan an advantage roll be a critical hit?Is there a way to make the Elven Accuracy feat work with the second benefit of Great Weapon Master?How does forgoing advantage interact with Elven Accuracy?Is this critical hit damage calculation correct?Are these two methods of handling Elven Accuracy “Double Advantage” mathematically equivalent?What are my chances of rolling a natural 19/20 critical if I roll 3d20?Does the advantage reroll of Elven Accuracy only apply to the ability you increased?
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty margin-bottom:0;
$begingroup$
I have Elven Accuracy so with advantage on an attack roll using Dexterity, Intelligence, Wisdom, or Charisma, you can reroll one of the dice once.
So what are my crit chance with a crit range of 18/20 with three rolls also what would be the crit chance with a crit range of 17/20 with three rolls.
dnd-5e statistics critical-hit
New contributor
Braymal Gaming is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$
add a comment |
$begingroup$
I have Elven Accuracy so with advantage on an attack roll using Dexterity, Intelligence, Wisdom, or Charisma, you can reroll one of the dice once.
So what are my crit chance with a crit range of 18/20 with three rolls also what would be the crit chance with a crit range of 17/20 with three rolls.
dnd-5e statistics critical-hit
New contributor
Braymal Gaming is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
1
$begingroup$
The notation you're using for the crit range is unusual. Are you describing a Champion Fighter? If so, where are you getting the 17/20 range from?
$endgroup$
– Xirema
4 hours ago
1
$begingroup$
What class/sub class is your character?
$endgroup$
– KorvinStarmast
4 hours ago
1
$begingroup$
Possible duplicate of What are my chances of rolling a natural 19/20 critical if I roll 3d20?
$endgroup$
– Julien Lopez
2 hours ago
add a comment |
$begingroup$
I have Elven Accuracy so with advantage on an attack roll using Dexterity, Intelligence, Wisdom, or Charisma, you can reroll one of the dice once.
So what are my crit chance with a crit range of 18/20 with three rolls also what would be the crit chance with a crit range of 17/20 with three rolls.
dnd-5e statistics critical-hit
New contributor
Braymal Gaming is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
I have Elven Accuracy so with advantage on an attack roll using Dexterity, Intelligence, Wisdom, or Charisma, you can reroll one of the dice once.
So what are my crit chance with a crit range of 18/20 with three rolls also what would be the crit chance with a crit range of 17/20 with three rolls.
dnd-5e statistics critical-hit
dnd-5e statistics critical-hit
New contributor
Braymal Gaming is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Braymal Gaming is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 3 hours ago
divibisan
1,729520
1,729520
New contributor
Braymal Gaming is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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asked 4 hours ago
Braymal GamingBraymal Gaming
412
412
New contributor
Braymal Gaming is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
Braymal Gaming is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
Braymal Gaming is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
1
$begingroup$
The notation you're using for the crit range is unusual. Are you describing a Champion Fighter? If so, where are you getting the 17/20 range from?
$endgroup$
– Xirema
4 hours ago
1
$begingroup$
What class/sub class is your character?
$endgroup$
– KorvinStarmast
4 hours ago
1
$begingroup$
Possible duplicate of What are my chances of rolling a natural 19/20 critical if I roll 3d20?
$endgroup$
– Julien Lopez
2 hours ago
add a comment |
1
$begingroup$
The notation you're using for the crit range is unusual. Are you describing a Champion Fighter? If so, where are you getting the 17/20 range from?
$endgroup$
– Xirema
4 hours ago
1
$begingroup$
What class/sub class is your character?
$endgroup$
– KorvinStarmast
4 hours ago
1
$begingroup$
Possible duplicate of What are my chances of rolling a natural 19/20 critical if I roll 3d20?
$endgroup$
– Julien Lopez
2 hours ago
1
1
$begingroup$
The notation you're using for the crit range is unusual. Are you describing a Champion Fighter? If so, where are you getting the 17/20 range from?
$endgroup$
– Xirema
4 hours ago
$begingroup$
The notation you're using for the crit range is unusual. Are you describing a Champion Fighter? If so, where are you getting the 17/20 range from?
$endgroup$
– Xirema
4 hours ago
1
1
$begingroup$
What class/sub class is your character?
$endgroup$
– KorvinStarmast
4 hours ago
$begingroup$
What class/sub class is your character?
$endgroup$
– KorvinStarmast
4 hours ago
1
1
$begingroup$
Possible duplicate of What are my chances of rolling a natural 19/20 critical if I roll 3d20?
$endgroup$
– Julien Lopez
2 hours ago
$begingroup$
Possible duplicate of What are my chances of rolling a natural 19/20 critical if I roll 3d20?
$endgroup$
– Julien Lopez
2 hours ago
add a comment |
4 Answers
4
active
oldest
votes
$begingroup$
For "at least one" probability problems, it's usually easier to start by calculating the chance that none of the dice crit, as that saves you the hassle of combining the probabilities of getting 1/2/3 crits.
Best of three rolls with 18-20 crit range: ~39% chance to crit
Chance that a single die will not crit: 17/20 = 0.85
Chance that all three dice will not crit: (17/20) x (17/20) x (17/20) = 0.614125
Chance that at least one die will crit: 1 - (17/20)3 = 0.385875
Best of three rolls with 17-20 crit range: ~49% chance to crit
Chance that a single die will not crit: 16/20 = 0.8
Chance that all three dice will not crit: (16/20) x (16/20) x (16/20) = 0.512
Chance that at least one die will crit: 1 - (16/20)3 = 0.488
$endgroup$
add a comment |
$begingroup$
The other answers do a good job of answering the question, but I'll point out how you can answer questions like this in the future:
https://anydice.com/ is a very powerful (if slightly complicated) calculator for these sorts of questions. In your case, you'd enter the query:
output [highest 1 of 3d20]
And then select "At Least" from options below to get this table, which shows the odds of getting at least each number:

The result, is 38.59% for a crit range of 18, and 48.8% for a crit range of 17
$endgroup$
add a comment |
$begingroup$
If p is the probability of a crit on a single role, then 1-(1-p)^N is the probability of at least one crit on N roles.
so for N=3 and p=3/20, P=38.6%
for crit range 17-20, P=48.8% (WOW!)
$endgroup$
$begingroup$
so noted. I have now edited my answer
$endgroup$
– Jeremy
4 hours ago
add a comment |
$begingroup$
It depends on how you use the Elven Accuracy Die
There's two ways that players are legally allowed to use the Elven Accuracy Die:
- Replace the lower of the two advantage dice (Type A)
- Replace the higher of the two advantage dice (Type B)
In the former case, this roll is mathematically equivalent to rolling 3 dice and taking the highest. In the latter case, it's more like rolling two dice, taking the lower, and then taking the higher of that result and a third die.
beginarrayr
textOutcomes & text18-20 A & text18-20 B
\ hline
textNon-Crit & text61.413% & text83.088% \
textCrit & text38.588% & text16.913% \
endarray
beginarrayr
& text17-20 A & text17-20 B \ hline
textNon-Crit & text51.200% & text76.800% \
textCrit & text48.800% & text23.200% \
endarray
Note: as far as I'm aware, in 5th Edition D&D, it is not possible to get a Critical hit range that includes 17. It's possible I'm unaware of a specific class feature or magic item that is expanding the range beyond what can be attained by a Champion Fighter at level 15. But as a result, the second table (the 17-20 range) does not have practical use in this game.
$endgroup$
$begingroup$
The one scenario I could imagine is if you're given advantage on a roll but explicitly want to avoid a critical hit (like you're trying to take down a target alive); Method B improves your odds of hitting while having a relatively minor impact on critical hit chance.
$endgroup$
– Xirema
4 hours ago
1
$begingroup$
That seems a bit convoluted since the rerolling is optional but I suppose it doesn't hurt to have the extra data.
$endgroup$
– Sdjz
4 hours ago
add a comment |
Your Answer
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4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
For "at least one" probability problems, it's usually easier to start by calculating the chance that none of the dice crit, as that saves you the hassle of combining the probabilities of getting 1/2/3 crits.
Best of three rolls with 18-20 crit range: ~39% chance to crit
Chance that a single die will not crit: 17/20 = 0.85
Chance that all three dice will not crit: (17/20) x (17/20) x (17/20) = 0.614125
Chance that at least one die will crit: 1 - (17/20)3 = 0.385875
Best of three rolls with 17-20 crit range: ~49% chance to crit
Chance that a single die will not crit: 16/20 = 0.8
Chance that all three dice will not crit: (16/20) x (16/20) x (16/20) = 0.512
Chance that at least one die will crit: 1 - (16/20)3 = 0.488
$endgroup$
add a comment |
$begingroup$
For "at least one" probability problems, it's usually easier to start by calculating the chance that none of the dice crit, as that saves you the hassle of combining the probabilities of getting 1/2/3 crits.
Best of three rolls with 18-20 crit range: ~39% chance to crit
Chance that a single die will not crit: 17/20 = 0.85
Chance that all three dice will not crit: (17/20) x (17/20) x (17/20) = 0.614125
Chance that at least one die will crit: 1 - (17/20)3 = 0.385875
Best of three rolls with 17-20 crit range: ~49% chance to crit
Chance that a single die will not crit: 16/20 = 0.8
Chance that all three dice will not crit: (16/20) x (16/20) x (16/20) = 0.512
Chance that at least one die will crit: 1 - (16/20)3 = 0.488
$endgroup$
add a comment |
$begingroup$
For "at least one" probability problems, it's usually easier to start by calculating the chance that none of the dice crit, as that saves you the hassle of combining the probabilities of getting 1/2/3 crits.
Best of three rolls with 18-20 crit range: ~39% chance to crit
Chance that a single die will not crit: 17/20 = 0.85
Chance that all three dice will not crit: (17/20) x (17/20) x (17/20) = 0.614125
Chance that at least one die will crit: 1 - (17/20)3 = 0.385875
Best of three rolls with 17-20 crit range: ~49% chance to crit
Chance that a single die will not crit: 16/20 = 0.8
Chance that all three dice will not crit: (16/20) x (16/20) x (16/20) = 0.512
Chance that at least one die will crit: 1 - (16/20)3 = 0.488
$endgroup$
For "at least one" probability problems, it's usually easier to start by calculating the chance that none of the dice crit, as that saves you the hassle of combining the probabilities of getting 1/2/3 crits.
Best of three rolls with 18-20 crit range: ~39% chance to crit
Chance that a single die will not crit: 17/20 = 0.85
Chance that all three dice will not crit: (17/20) x (17/20) x (17/20) = 0.614125
Chance that at least one die will crit: 1 - (17/20)3 = 0.385875
Best of three rolls with 17-20 crit range: ~49% chance to crit
Chance that a single die will not crit: 16/20 = 0.8
Chance that all three dice will not crit: (16/20) x (16/20) x (16/20) = 0.512
Chance that at least one die will crit: 1 - (16/20)3 = 0.488
edited 1 hour ago
answered 4 hours ago
Oblivious SageOblivious Sage
43.4k14137199
43.4k14137199
add a comment |
add a comment |
$begingroup$
The other answers do a good job of answering the question, but I'll point out how you can answer questions like this in the future:
https://anydice.com/ is a very powerful (if slightly complicated) calculator for these sorts of questions. In your case, you'd enter the query:
output [highest 1 of 3d20]
And then select "At Least" from options below to get this table, which shows the odds of getting at least each number:

The result, is 38.59% for a crit range of 18, and 48.8% for a crit range of 17
$endgroup$
add a comment |
$begingroup$
The other answers do a good job of answering the question, but I'll point out how you can answer questions like this in the future:
https://anydice.com/ is a very powerful (if slightly complicated) calculator for these sorts of questions. In your case, you'd enter the query:
output [highest 1 of 3d20]
And then select "At Least" from options below to get this table, which shows the odds of getting at least each number:

The result, is 38.59% for a crit range of 18, and 48.8% for a crit range of 17
$endgroup$
add a comment |
$begingroup$
The other answers do a good job of answering the question, but I'll point out how you can answer questions like this in the future:
https://anydice.com/ is a very powerful (if slightly complicated) calculator for these sorts of questions. In your case, you'd enter the query:
output [highest 1 of 3d20]
And then select "At Least" from options below to get this table, which shows the odds of getting at least each number:

The result, is 38.59% for a crit range of 18, and 48.8% for a crit range of 17
$endgroup$
The other answers do a good job of answering the question, but I'll point out how you can answer questions like this in the future:
https://anydice.com/ is a very powerful (if slightly complicated) calculator for these sorts of questions. In your case, you'd enter the query:
output [highest 1 of 3d20]
And then select "At Least" from options below to get this table, which shows the odds of getting at least each number:

The result, is 38.59% for a crit range of 18, and 48.8% for a crit range of 17
edited 4 hours ago
Sdjz
14.1k467114
14.1k467114
answered 4 hours ago
divibisandivibisan
1,729520
1,729520
add a comment |
add a comment |
$begingroup$
If p is the probability of a crit on a single role, then 1-(1-p)^N is the probability of at least one crit on N roles.
so for N=3 and p=3/20, P=38.6%
for crit range 17-20, P=48.8% (WOW!)
$endgroup$
$begingroup$
so noted. I have now edited my answer
$endgroup$
– Jeremy
4 hours ago
add a comment |
$begingroup$
If p is the probability of a crit on a single role, then 1-(1-p)^N is the probability of at least one crit on N roles.
so for N=3 and p=3/20, P=38.6%
for crit range 17-20, P=48.8% (WOW!)
$endgroup$
$begingroup$
so noted. I have now edited my answer
$endgroup$
– Jeremy
4 hours ago
add a comment |
$begingroup$
If p is the probability of a crit on a single role, then 1-(1-p)^N is the probability of at least one crit on N roles.
so for N=3 and p=3/20, P=38.6%
for crit range 17-20, P=48.8% (WOW!)
$endgroup$
If p is the probability of a crit on a single role, then 1-(1-p)^N is the probability of at least one crit on N roles.
so for N=3 and p=3/20, P=38.6%
for crit range 17-20, P=48.8% (WOW!)
edited 4 hours ago
answered 4 hours ago
JeremyJeremy
1765
1765
$begingroup$
so noted. I have now edited my answer
$endgroup$
– Jeremy
4 hours ago
add a comment |
$begingroup$
so noted. I have now edited my answer
$endgroup$
– Jeremy
4 hours ago
$begingroup$
so noted. I have now edited my answer
$endgroup$
– Jeremy
4 hours ago
$begingroup$
so noted. I have now edited my answer
$endgroup$
– Jeremy
4 hours ago
add a comment |
$begingroup$
It depends on how you use the Elven Accuracy Die
There's two ways that players are legally allowed to use the Elven Accuracy Die:
- Replace the lower of the two advantage dice (Type A)
- Replace the higher of the two advantage dice (Type B)
In the former case, this roll is mathematically equivalent to rolling 3 dice and taking the highest. In the latter case, it's more like rolling two dice, taking the lower, and then taking the higher of that result and a third die.
beginarrayr
textOutcomes & text18-20 A & text18-20 B
\ hline
textNon-Crit & text61.413% & text83.088% \
textCrit & text38.588% & text16.913% \
endarray
beginarrayr
& text17-20 A & text17-20 B \ hline
textNon-Crit & text51.200% & text76.800% \
textCrit & text48.800% & text23.200% \
endarray
Note: as far as I'm aware, in 5th Edition D&D, it is not possible to get a Critical hit range that includes 17. It's possible I'm unaware of a specific class feature or magic item that is expanding the range beyond what can be attained by a Champion Fighter at level 15. But as a result, the second table (the 17-20 range) does not have practical use in this game.
$endgroup$
$begingroup$
The one scenario I could imagine is if you're given advantage on a roll but explicitly want to avoid a critical hit (like you're trying to take down a target alive); Method B improves your odds of hitting while having a relatively minor impact on critical hit chance.
$endgroup$
– Xirema
4 hours ago
1
$begingroup$
That seems a bit convoluted since the rerolling is optional but I suppose it doesn't hurt to have the extra data.
$endgroup$
– Sdjz
4 hours ago
add a comment |
$begingroup$
It depends on how you use the Elven Accuracy Die
There's two ways that players are legally allowed to use the Elven Accuracy Die:
- Replace the lower of the two advantage dice (Type A)
- Replace the higher of the two advantage dice (Type B)
In the former case, this roll is mathematically equivalent to rolling 3 dice and taking the highest. In the latter case, it's more like rolling two dice, taking the lower, and then taking the higher of that result and a third die.
beginarrayr
textOutcomes & text18-20 A & text18-20 B
\ hline
textNon-Crit & text61.413% & text83.088% \
textCrit & text38.588% & text16.913% \
endarray
beginarrayr
& text17-20 A & text17-20 B \ hline
textNon-Crit & text51.200% & text76.800% \
textCrit & text48.800% & text23.200% \
endarray
Note: as far as I'm aware, in 5th Edition D&D, it is not possible to get a Critical hit range that includes 17. It's possible I'm unaware of a specific class feature or magic item that is expanding the range beyond what can be attained by a Champion Fighter at level 15. But as a result, the second table (the 17-20 range) does not have practical use in this game.
$endgroup$
$begingroup$
The one scenario I could imagine is if you're given advantage on a roll but explicitly want to avoid a critical hit (like you're trying to take down a target alive); Method B improves your odds of hitting while having a relatively minor impact on critical hit chance.
$endgroup$
– Xirema
4 hours ago
1
$begingroup$
That seems a bit convoluted since the rerolling is optional but I suppose it doesn't hurt to have the extra data.
$endgroup$
– Sdjz
4 hours ago
add a comment |
$begingroup$
It depends on how you use the Elven Accuracy Die
There's two ways that players are legally allowed to use the Elven Accuracy Die:
- Replace the lower of the two advantage dice (Type A)
- Replace the higher of the two advantage dice (Type B)
In the former case, this roll is mathematically equivalent to rolling 3 dice and taking the highest. In the latter case, it's more like rolling two dice, taking the lower, and then taking the higher of that result and a third die.
beginarrayr
textOutcomes & text18-20 A & text18-20 B
\ hline
textNon-Crit & text61.413% & text83.088% \
textCrit & text38.588% & text16.913% \
endarray
beginarrayr
& text17-20 A & text17-20 B \ hline
textNon-Crit & text51.200% & text76.800% \
textCrit & text48.800% & text23.200% \
endarray
Note: as far as I'm aware, in 5th Edition D&D, it is not possible to get a Critical hit range that includes 17. It's possible I'm unaware of a specific class feature or magic item that is expanding the range beyond what can be attained by a Champion Fighter at level 15. But as a result, the second table (the 17-20 range) does not have practical use in this game.
$endgroup$
It depends on how you use the Elven Accuracy Die
There's two ways that players are legally allowed to use the Elven Accuracy Die:
- Replace the lower of the two advantage dice (Type A)
- Replace the higher of the two advantage dice (Type B)
In the former case, this roll is mathematically equivalent to rolling 3 dice and taking the highest. In the latter case, it's more like rolling two dice, taking the lower, and then taking the higher of that result and a third die.
beginarrayr
textOutcomes & text18-20 A & text18-20 B
\ hline
textNon-Crit & text61.413% & text83.088% \
textCrit & text38.588% & text16.913% \
endarray
beginarrayr
& text17-20 A & text17-20 B \ hline
textNon-Crit & text51.200% & text76.800% \
textCrit & text48.800% & text23.200% \
endarray
Note: as far as I'm aware, in 5th Edition D&D, it is not possible to get a Critical hit range that includes 17. It's possible I'm unaware of a specific class feature or magic item that is expanding the range beyond what can be attained by a Champion Fighter at level 15. But as a result, the second table (the 17-20 range) does not have practical use in this game.
answered 4 hours ago
XiremaXirema
23.8k268140
23.8k268140
$begingroup$
The one scenario I could imagine is if you're given advantage on a roll but explicitly want to avoid a critical hit (like you're trying to take down a target alive); Method B improves your odds of hitting while having a relatively minor impact on critical hit chance.
$endgroup$
– Xirema
4 hours ago
1
$begingroup$
That seems a bit convoluted since the rerolling is optional but I suppose it doesn't hurt to have the extra data.
$endgroup$
– Sdjz
4 hours ago
add a comment |
$begingroup$
The one scenario I could imagine is if you're given advantage on a roll but explicitly want to avoid a critical hit (like you're trying to take down a target alive); Method B improves your odds of hitting while having a relatively minor impact on critical hit chance.
$endgroup$
– Xirema
4 hours ago
1
$begingroup$
That seems a bit convoluted since the rerolling is optional but I suppose it doesn't hurt to have the extra data.
$endgroup$
– Sdjz
4 hours ago
$begingroup$
The one scenario I could imagine is if you're given advantage on a roll but explicitly want to avoid a critical hit (like you're trying to take down a target alive); Method B improves your odds of hitting while having a relatively minor impact on critical hit chance.
$endgroup$
– Xirema
4 hours ago
$begingroup$
The one scenario I could imagine is if you're given advantage on a roll but explicitly want to avoid a critical hit (like you're trying to take down a target alive); Method B improves your odds of hitting while having a relatively minor impact on critical hit chance.
$endgroup$
– Xirema
4 hours ago
1
1
$begingroup$
That seems a bit convoluted since the rerolling is optional but I suppose it doesn't hurt to have the extra data.
$endgroup$
– Sdjz
4 hours ago
$begingroup$
That seems a bit convoluted since the rerolling is optional but I suppose it doesn't hurt to have the extra data.
$endgroup$
– Sdjz
4 hours ago
add a comment |
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1
$begingroup$
The notation you're using for the crit range is unusual. Are you describing a Champion Fighter? If so, where are you getting the 17/20 range from?
$endgroup$
– Xirema
4 hours ago
1
$begingroup$
What class/sub class is your character?
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– KorvinStarmast
4 hours ago
1
$begingroup$
Possible duplicate of What are my chances of rolling a natural 19/20 critical if I roll 3d20?
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– Julien Lopez
2 hours ago