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Gantt Chart like rectangles with log scale


Poets of the 19th centuryIs there a way to output histogram x and y data without using the Histogram chart function?BarChart and Log Scale results in different bar originsIssue with ListDensityPlot when using logarithmic scaleHow to plot BarChart with error bars on logarithmic scale in Mathematica 9?How to plot two y axis? or combine(merge) two plots? Should handle faceted column as wellJumping from one dimension (1D) to two dimensions (2D)Jumping from one dimension (1D) to two dimensions (2D) Part IIWavelet Data Visualization (modus and phase) ListPlotBar chart scale in multi-chart visualisationUpdate: Combining DistributionChart and BoxWhiskerChart













5












$begingroup$


I need to plot something that looks like a gant chart, but are actual data ranges. These ranges need to be on a log scale. Graphics does not offer a Scalingfunction. A LogPlot with ErrorBars does not work either and would not look ideal. Is it possible to draw rectangles with one axis being log scale?



E.g.:
Min and Max values of the rectangles are the known data.



enter image description here










share|improve this question











$endgroup$







  • 1




    $begingroup$
    Can you point to an example (even a non-Mathematica example)?
    $endgroup$
    – David G. Stork
    5 hours ago















5












$begingroup$


I need to plot something that looks like a gant chart, but are actual data ranges. These ranges need to be on a log scale. Graphics does not offer a Scalingfunction. A LogPlot with ErrorBars does not work either and would not look ideal. Is it possible to draw rectangles with one axis being log scale?



E.g.:
Min and Max values of the rectangles are the known data.



enter image description here










share|improve this question











$endgroup$







  • 1




    $begingroup$
    Can you point to an example (even a non-Mathematica example)?
    $endgroup$
    – David G. Stork
    5 hours ago













5












5








5





$begingroup$


I need to plot something that looks like a gant chart, but are actual data ranges. These ranges need to be on a log scale. Graphics does not offer a Scalingfunction. A LogPlot with ErrorBars does not work either and would not look ideal. Is it possible to draw rectangles with one axis being log scale?



E.g.:
Min and Max values of the rectangles are the known data.



enter image description here










share|improve this question











$endgroup$




I need to plot something that looks like a gant chart, but are actual data ranges. These ranges need to be on a log scale. Graphics does not offer a Scalingfunction. A LogPlot with ErrorBars does not work either and would not look ideal. Is it possible to draw rectangles with one axis being log scale?



E.g.:
Min and Max values of the rectangles are the known data.



enter image description here







plotting charts






share|improve this question















share|improve this question













share|improve this question




share|improve this question








edited 5 hours ago







Mockup Dungeon

















asked 5 hours ago









Mockup DungeonMockup Dungeon

888613




888613







  • 1




    $begingroup$
    Can you point to an example (even a non-Mathematica example)?
    $endgroup$
    – David G. Stork
    5 hours ago












  • 1




    $begingroup$
    Can you point to an example (even a non-Mathematica example)?
    $endgroup$
    – David G. Stork
    5 hours ago







1




1




$begingroup$
Can you point to an example (even a non-Mathematica example)?
$endgroup$
– David G. Stork
5 hours ago




$begingroup$
Can you point to an example (even a non-Mathematica example)?
$endgroup$
– David G. Stork
5 hours ago










3 Answers
3






active

oldest

votes


















5












$begingroup$

SeedRandom[1]
dates = Sort /@ RandomInteger[10, 1000, 5, 2];
data = MapIndexed[Thread@#, #2[[1]] &, dates];
labels = CharacterRange["A", "E"];
data2 = MapIndexed[Labeled[#, #2[[1]], Style[labels[[#2[[1]]]], White,
FontSize -> Scaled[.03]], Center] &, N[GeometricMean /@ dates]];


ListLogLinearPlot



Show[ListLogLinearPlot[data, 
BaseStyle -> Directive[AbsoluteThickness[36], CapForm["Butt"]],
Joined -> True, AspectRatio -> 1/2, ImageSize -> Large,
PlotRange -> 0, 6, Frame -> True,
FrameTicks -> None, None, 50, 100, 200, 500, 1000, Automatic],
ListLogLinearPlot[data2, PlotMarkers -> ""]]


enter image description here



TimeLinePlot



TimelinePlot[Labeled[#, Style[#2, White, FontSize -> Scaled[.03]], Center] & @@@ 
Transpose[Interval /@ (Map[N@*Log, dates, -1]), labels],
PlotStyle -> Directive[AbsoluteThickness[40], CapForm["Butt"]],
Spacings -> .1, PlotMarkers -> "", Frame -> True,
AspectRatio -> 1/2, PerformanceGoal -> "Speed",
FrameTicks -> Automatic, Automatic,
Transpose[N@Log@#, # &@50, 100, 200, 500], None]


enter image description here



Thanks: @David G. Stork for the GeometricMean idea to center the labels.



See also: Poets of the 19th century






share|improve this answer











$endgroup$








  • 1




    $begingroup$
    The only needed improvement: take the geometric mean of each bar's endpoints to get the "middle" placement of the letter. Mean is simply incorrect. Try GeometricMean.
    $endgroup$
    – David G. Stork
    4 hours ago











  • $begingroup$
    Thank you @David! I was struggling with exactly that issue.
    $endgroup$
    – kglr
    4 hours ago


















3












$begingroup$

LogLinearPlot[1, 
t, .1, 100,
PlotStyle -> White,
Epilog -> Rectangle[Log[1], .5, Log[50], 1],
Red, Rectangle[Log[30], 1.5, Log[80], 2],
Text[Style["a", White, 18], Log[7], .75],
Text[Style["b", White, 18], Log[53], 1.75]]





share|improve this answer











$endgroup$












  • $begingroup$
    This is nice, was wondering how to use Rectangle[]. Thank you!
    $endgroup$
    – mjw
    4 hours ago


















0












$begingroup$

Here is a start ...



A = 10^5; B = 10; 
rectangle[start_, length_, number_] := RegionPlot[Log10[start] <= x <= Log10[start + length] && number <= y <= number + .75, x, 0, Log10[A], y, 0, B];


Then we place a few rectangle[]'s in Show[].



Show[rectangle[100, 300, 2], rectangle[200, 2000, 3], rectangle[1300, 3000, 4], rectangle[1800, 9000, 5]]


We now need to change the tick-marks and x-axis labels. I wanted to use ScalingFunction->"Log10",Automatic but this is not a valid argument for RegionPlot[].



Here is how it looks right now:



enter image description here



With your edits, we can get the x-axis looking better! Currently the x-axis label is $log_10 x $ and not $x$ as we would like.






share|improve this answer











$endgroup$












  • $begingroup$
    Axis-Ticks should not be a problem. I'll check tomorrow. It's now night here.
    $endgroup$
    – Mockup Dungeon
    4 hours ago










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3 Answers
3






active

oldest

votes








3 Answers
3






active

oldest

votes









active

oldest

votes






active

oldest

votes









5












$begingroup$

SeedRandom[1]
dates = Sort /@ RandomInteger[10, 1000, 5, 2];
data = MapIndexed[Thread@#, #2[[1]] &, dates];
labels = CharacterRange["A", "E"];
data2 = MapIndexed[Labeled[#, #2[[1]], Style[labels[[#2[[1]]]], White,
FontSize -> Scaled[.03]], Center] &, N[GeometricMean /@ dates]];


ListLogLinearPlot



Show[ListLogLinearPlot[data, 
BaseStyle -> Directive[AbsoluteThickness[36], CapForm["Butt"]],
Joined -> True, AspectRatio -> 1/2, ImageSize -> Large,
PlotRange -> 0, 6, Frame -> True,
FrameTicks -> None, None, 50, 100, 200, 500, 1000, Automatic],
ListLogLinearPlot[data2, PlotMarkers -> ""]]


enter image description here



TimeLinePlot



TimelinePlot[Labeled[#, Style[#2, White, FontSize -> Scaled[.03]], Center] & @@@ 
Transpose[Interval /@ (Map[N@*Log, dates, -1]), labels],
PlotStyle -> Directive[AbsoluteThickness[40], CapForm["Butt"]],
Spacings -> .1, PlotMarkers -> "", Frame -> True,
AspectRatio -> 1/2, PerformanceGoal -> "Speed",
FrameTicks -> Automatic, Automatic,
Transpose[N@Log@#, # &@50, 100, 200, 500], None]


enter image description here



Thanks: @David G. Stork for the GeometricMean idea to center the labels.



See also: Poets of the 19th century






share|improve this answer











$endgroup$








  • 1




    $begingroup$
    The only needed improvement: take the geometric mean of each bar's endpoints to get the "middle" placement of the letter. Mean is simply incorrect. Try GeometricMean.
    $endgroup$
    – David G. Stork
    4 hours ago











  • $begingroup$
    Thank you @David! I was struggling with exactly that issue.
    $endgroup$
    – kglr
    4 hours ago















5












$begingroup$

SeedRandom[1]
dates = Sort /@ RandomInteger[10, 1000, 5, 2];
data = MapIndexed[Thread@#, #2[[1]] &, dates];
labels = CharacterRange["A", "E"];
data2 = MapIndexed[Labeled[#, #2[[1]], Style[labels[[#2[[1]]]], White,
FontSize -> Scaled[.03]], Center] &, N[GeometricMean /@ dates]];


ListLogLinearPlot



Show[ListLogLinearPlot[data, 
BaseStyle -> Directive[AbsoluteThickness[36], CapForm["Butt"]],
Joined -> True, AspectRatio -> 1/2, ImageSize -> Large,
PlotRange -> 0, 6, Frame -> True,
FrameTicks -> None, None, 50, 100, 200, 500, 1000, Automatic],
ListLogLinearPlot[data2, PlotMarkers -> ""]]


enter image description here



TimeLinePlot



TimelinePlot[Labeled[#, Style[#2, White, FontSize -> Scaled[.03]], Center] & @@@ 
Transpose[Interval /@ (Map[N@*Log, dates, -1]), labels],
PlotStyle -> Directive[AbsoluteThickness[40], CapForm["Butt"]],
Spacings -> .1, PlotMarkers -> "", Frame -> True,
AspectRatio -> 1/2, PerformanceGoal -> "Speed",
FrameTicks -> Automatic, Automatic,
Transpose[N@Log@#, # &@50, 100, 200, 500], None]


enter image description here



Thanks: @David G. Stork for the GeometricMean idea to center the labels.



See also: Poets of the 19th century






share|improve this answer











$endgroup$








  • 1




    $begingroup$
    The only needed improvement: take the geometric mean of each bar's endpoints to get the "middle" placement of the letter. Mean is simply incorrect. Try GeometricMean.
    $endgroup$
    – David G. Stork
    4 hours ago











  • $begingroup$
    Thank you @David! I was struggling with exactly that issue.
    $endgroup$
    – kglr
    4 hours ago













5












5








5





$begingroup$

SeedRandom[1]
dates = Sort /@ RandomInteger[10, 1000, 5, 2];
data = MapIndexed[Thread@#, #2[[1]] &, dates];
labels = CharacterRange["A", "E"];
data2 = MapIndexed[Labeled[#, #2[[1]], Style[labels[[#2[[1]]]], White,
FontSize -> Scaled[.03]], Center] &, N[GeometricMean /@ dates]];


ListLogLinearPlot



Show[ListLogLinearPlot[data, 
BaseStyle -> Directive[AbsoluteThickness[36], CapForm["Butt"]],
Joined -> True, AspectRatio -> 1/2, ImageSize -> Large,
PlotRange -> 0, 6, Frame -> True,
FrameTicks -> None, None, 50, 100, 200, 500, 1000, Automatic],
ListLogLinearPlot[data2, PlotMarkers -> ""]]


enter image description here



TimeLinePlot



TimelinePlot[Labeled[#, Style[#2, White, FontSize -> Scaled[.03]], Center] & @@@ 
Transpose[Interval /@ (Map[N@*Log, dates, -1]), labels],
PlotStyle -> Directive[AbsoluteThickness[40], CapForm["Butt"]],
Spacings -> .1, PlotMarkers -> "", Frame -> True,
AspectRatio -> 1/2, PerformanceGoal -> "Speed",
FrameTicks -> Automatic, Automatic,
Transpose[N@Log@#, # &@50, 100, 200, 500], None]


enter image description here



Thanks: @David G. Stork for the GeometricMean idea to center the labels.



See also: Poets of the 19th century






share|improve this answer











$endgroup$



SeedRandom[1]
dates = Sort /@ RandomInteger[10, 1000, 5, 2];
data = MapIndexed[Thread@#, #2[[1]] &, dates];
labels = CharacterRange["A", "E"];
data2 = MapIndexed[Labeled[#, #2[[1]], Style[labels[[#2[[1]]]], White,
FontSize -> Scaled[.03]], Center] &, N[GeometricMean /@ dates]];


ListLogLinearPlot



Show[ListLogLinearPlot[data, 
BaseStyle -> Directive[AbsoluteThickness[36], CapForm["Butt"]],
Joined -> True, AspectRatio -> 1/2, ImageSize -> Large,
PlotRange -> 0, 6, Frame -> True,
FrameTicks -> None, None, 50, 100, 200, 500, 1000, Automatic],
ListLogLinearPlot[data2, PlotMarkers -> ""]]


enter image description here



TimeLinePlot



TimelinePlot[Labeled[#, Style[#2, White, FontSize -> Scaled[.03]], Center] & @@@ 
Transpose[Interval /@ (Map[N@*Log, dates, -1]), labels],
PlotStyle -> Directive[AbsoluteThickness[40], CapForm["Butt"]],
Spacings -> .1, PlotMarkers -> "", Frame -> True,
AspectRatio -> 1/2, PerformanceGoal -> "Speed",
FrameTicks -> Automatic, Automatic,
Transpose[N@Log@#, # &@50, 100, 200, 500], None]


enter image description here



Thanks: @David G. Stork for the GeometricMean idea to center the labels.



See also: Poets of the 19th century







share|improve this answer














share|improve this answer



share|improve this answer








edited 12 mins ago

























answered 4 hours ago









kglrkglr

189k10205422




189k10205422







  • 1




    $begingroup$
    The only needed improvement: take the geometric mean of each bar's endpoints to get the "middle" placement of the letter. Mean is simply incorrect. Try GeometricMean.
    $endgroup$
    – David G. Stork
    4 hours ago











  • $begingroup$
    Thank you @David! I was struggling with exactly that issue.
    $endgroup$
    – kglr
    4 hours ago












  • 1




    $begingroup$
    The only needed improvement: take the geometric mean of each bar's endpoints to get the "middle" placement of the letter. Mean is simply incorrect. Try GeometricMean.
    $endgroup$
    – David G. Stork
    4 hours ago











  • $begingroup$
    Thank you @David! I was struggling with exactly that issue.
    $endgroup$
    – kglr
    4 hours ago







1




1




$begingroup$
The only needed improvement: take the geometric mean of each bar's endpoints to get the "middle" placement of the letter. Mean is simply incorrect. Try GeometricMean.
$endgroup$
– David G. Stork
4 hours ago





$begingroup$
The only needed improvement: take the geometric mean of each bar's endpoints to get the "middle" placement of the letter. Mean is simply incorrect. Try GeometricMean.
$endgroup$
– David G. Stork
4 hours ago













$begingroup$
Thank you @David! I was struggling with exactly that issue.
$endgroup$
– kglr
4 hours ago




$begingroup$
Thank you @David! I was struggling with exactly that issue.
$endgroup$
– kglr
4 hours ago











3












$begingroup$

LogLinearPlot[1, 
t, .1, 100,
PlotStyle -> White,
Epilog -> Rectangle[Log[1], .5, Log[50], 1],
Red, Rectangle[Log[30], 1.5, Log[80], 2],
Text[Style["a", White, 18], Log[7], .75],
Text[Style["b", White, 18], Log[53], 1.75]]





share|improve this answer











$endgroup$












  • $begingroup$
    This is nice, was wondering how to use Rectangle[]. Thank you!
    $endgroup$
    – mjw
    4 hours ago















3












$begingroup$

LogLinearPlot[1, 
t, .1, 100,
PlotStyle -> White,
Epilog -> Rectangle[Log[1], .5, Log[50], 1],
Red, Rectangle[Log[30], 1.5, Log[80], 2],
Text[Style["a", White, 18], Log[7], .75],
Text[Style["b", White, 18], Log[53], 1.75]]





share|improve this answer











$endgroup$












  • $begingroup$
    This is nice, was wondering how to use Rectangle[]. Thank you!
    $endgroup$
    – mjw
    4 hours ago













3












3








3





$begingroup$

LogLinearPlot[1, 
t, .1, 100,
PlotStyle -> White,
Epilog -> Rectangle[Log[1], .5, Log[50], 1],
Red, Rectangle[Log[30], 1.5, Log[80], 2],
Text[Style["a", White, 18], Log[7], .75],
Text[Style["b", White, 18], Log[53], 1.75]]





share|improve this answer











$endgroup$



LogLinearPlot[1, 
t, .1, 100,
PlotStyle -> White,
Epilog -> Rectangle[Log[1], .5, Log[50], 1],
Red, Rectangle[Log[30], 1.5, Log[80], 2],
Text[Style["a", White, 18], Log[7], .75],
Text[Style["b", White, 18], Log[53], 1.75]]






share|improve this answer














share|improve this answer



share|improve this answer








edited 4 hours ago

























answered 4 hours ago









David G. StorkDavid G. Stork

24.6k22153




24.6k22153











  • $begingroup$
    This is nice, was wondering how to use Rectangle[]. Thank you!
    $endgroup$
    – mjw
    4 hours ago
















  • $begingroup$
    This is nice, was wondering how to use Rectangle[]. Thank you!
    $endgroup$
    – mjw
    4 hours ago















$begingroup$
This is nice, was wondering how to use Rectangle[]. Thank you!
$endgroup$
– mjw
4 hours ago




$begingroup$
This is nice, was wondering how to use Rectangle[]. Thank you!
$endgroup$
– mjw
4 hours ago











0












$begingroup$

Here is a start ...



A = 10^5; B = 10; 
rectangle[start_, length_, number_] := RegionPlot[Log10[start] <= x <= Log10[start + length] && number <= y <= number + .75, x, 0, Log10[A], y, 0, B];


Then we place a few rectangle[]'s in Show[].



Show[rectangle[100, 300, 2], rectangle[200, 2000, 3], rectangle[1300, 3000, 4], rectangle[1800, 9000, 5]]


We now need to change the tick-marks and x-axis labels. I wanted to use ScalingFunction->"Log10",Automatic but this is not a valid argument for RegionPlot[].



Here is how it looks right now:



enter image description here



With your edits, we can get the x-axis looking better! Currently the x-axis label is $log_10 x $ and not $x$ as we would like.






share|improve this answer











$endgroup$












  • $begingroup$
    Axis-Ticks should not be a problem. I'll check tomorrow. It's now night here.
    $endgroup$
    – Mockup Dungeon
    4 hours ago















0












$begingroup$

Here is a start ...



A = 10^5; B = 10; 
rectangle[start_, length_, number_] := RegionPlot[Log10[start] <= x <= Log10[start + length] && number <= y <= number + .75, x, 0, Log10[A], y, 0, B];


Then we place a few rectangle[]'s in Show[].



Show[rectangle[100, 300, 2], rectangle[200, 2000, 3], rectangle[1300, 3000, 4], rectangle[1800, 9000, 5]]


We now need to change the tick-marks and x-axis labels. I wanted to use ScalingFunction->"Log10",Automatic but this is not a valid argument for RegionPlot[].



Here is how it looks right now:



enter image description here



With your edits, we can get the x-axis looking better! Currently the x-axis label is $log_10 x $ and not $x$ as we would like.






share|improve this answer











$endgroup$












  • $begingroup$
    Axis-Ticks should not be a problem. I'll check tomorrow. It's now night here.
    $endgroup$
    – Mockup Dungeon
    4 hours ago













0












0








0





$begingroup$

Here is a start ...



A = 10^5; B = 10; 
rectangle[start_, length_, number_] := RegionPlot[Log10[start] <= x <= Log10[start + length] && number <= y <= number + .75, x, 0, Log10[A], y, 0, B];


Then we place a few rectangle[]'s in Show[].



Show[rectangle[100, 300, 2], rectangle[200, 2000, 3], rectangle[1300, 3000, 4], rectangle[1800, 9000, 5]]


We now need to change the tick-marks and x-axis labels. I wanted to use ScalingFunction->"Log10",Automatic but this is not a valid argument for RegionPlot[].



Here is how it looks right now:



enter image description here



With your edits, we can get the x-axis looking better! Currently the x-axis label is $log_10 x $ and not $x$ as we would like.






share|improve this answer











$endgroup$



Here is a start ...



A = 10^5; B = 10; 
rectangle[start_, length_, number_] := RegionPlot[Log10[start] <= x <= Log10[start + length] && number <= y <= number + .75, x, 0, Log10[A], y, 0, B];


Then we place a few rectangle[]'s in Show[].



Show[rectangle[100, 300, 2], rectangle[200, 2000, 3], rectangle[1300, 3000, 4], rectangle[1800, 9000, 5]]


We now need to change the tick-marks and x-axis labels. I wanted to use ScalingFunction->"Log10",Automatic but this is not a valid argument for RegionPlot[].



Here is how it looks right now:



enter image description here



With your edits, we can get the x-axis looking better! Currently the x-axis label is $log_10 x $ and not $x$ as we would like.







share|improve this answer














share|improve this answer



share|improve this answer








edited 4 hours ago

























answered 5 hours ago









mjwmjw

5879




5879











  • $begingroup$
    Axis-Ticks should not be a problem. I'll check tomorrow. It's now night here.
    $endgroup$
    – Mockup Dungeon
    4 hours ago
















  • $begingroup$
    Axis-Ticks should not be a problem. I'll check tomorrow. It's now night here.
    $endgroup$
    – Mockup Dungeon
    4 hours ago















$begingroup$
Axis-Ticks should not be a problem. I'll check tomorrow. It's now night here.
$endgroup$
– Mockup Dungeon
4 hours ago




$begingroup$
Axis-Ticks should not be a problem. I'll check tomorrow. It's now night here.
$endgroup$
– Mockup Dungeon
4 hours ago

















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