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Recursive calls to a function - why is the address of the parameter passed to it lowering with each call?



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern)
Data science time! April 2019 and salary with experience
The Ask Question Wizard is Live!What is the direction of stack growth in most modern systems?Why isn't sizeof for a struct equal to the sum of sizeof of each member?How to call a parent class function from derived class function?Why do we need virtual functions in C++?Pretty-print C++ STL containersHow to pass normal param as well as template param in a template function in C++?Are the days of passing const std::string & as a parameter over?Recursive Reverse FunctionWhy can I not move unique_ptr from a set to a function argument using an iterator?Why can I not call reserve on a vector of const elements?Having issues with .h file, it doesn't seem to be linking correctly



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7















Consider following code:



#include <iostream>
using namespace std;
void test_func(int address)
cout<<&address<<" ";
if(address < 0x7FFBEE26)
test_func(address);


int main()

test_func(512);
cout<<"Hello";
return 0;



Hello from main() is certainly not reached, since the recursive calls to test_func never end.



However, from what I can see in the cout present in test_func - the addresses being printed are lower and lower with each iteration. Why is that happening?










share|improve this question









New contributor




tears allo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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  • 1





    You are passing a copy - that has to have an address

    – UnholySheep
    1 hour ago






  • 1





    Remember that the default stack size on linux is 10MB and its 1 MB on windows. Also the stack need not be in the same location each time you run your program.

    – drescherjm
    1 hour ago












  • I can't understand why this isn't eligible for tail-call optimization. The invocation of test_func is the last line in the function...

    – cyberbisson
    50 mins ago


















7















Consider following code:



#include <iostream>
using namespace std;
void test_func(int address)
cout<<&address<<" ";
if(address < 0x7FFBEE26)
test_func(address);


int main()

test_func(512);
cout<<"Hello";
return 0;



Hello from main() is certainly not reached, since the recursive calls to test_func never end.



However, from what I can see in the cout present in test_func - the addresses being printed are lower and lower with each iteration. Why is that happening?










share|improve this question









New contributor




tears allo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.















  • 1





    You are passing a copy - that has to have an address

    – UnholySheep
    1 hour ago






  • 1





    Remember that the default stack size on linux is 10MB and its 1 MB on windows. Also the stack need not be in the same location each time you run your program.

    – drescherjm
    1 hour ago












  • I can't understand why this isn't eligible for tail-call optimization. The invocation of test_func is the last line in the function...

    – cyberbisson
    50 mins ago














7












7








7








Consider following code:



#include <iostream>
using namespace std;
void test_func(int address)
cout<<&address<<" ";
if(address < 0x7FFBEE26)
test_func(address);


int main()

test_func(512);
cout<<"Hello";
return 0;



Hello from main() is certainly not reached, since the recursive calls to test_func never end.



However, from what I can see in the cout present in test_func - the addresses being printed are lower and lower with each iteration. Why is that happening?










share|improve this question









New contributor




tears allo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.












Consider following code:



#include <iostream>
using namespace std;
void test_func(int address)
cout<<&address<<" ";
if(address < 0x7FFBEE26)
test_func(address);


int main()

test_func(512);
cout<<"Hello";
return 0;



Hello from main() is certainly not reached, since the recursive calls to test_func never end.



However, from what I can see in the cout present in test_func - the addresses being printed are lower and lower with each iteration. Why is that happening?







c++






share|improve this question









New contributor




tears allo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|improve this question









New contributor




tears allo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|improve this question




share|improve this question








edited 1 hour ago









drescherjm

6,59923553




6,59923553






New contributor




tears allo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 1 hour ago









tears allotears allo

361




361




New contributor




tears allo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





tears allo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






tears allo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







  • 1





    You are passing a copy - that has to have an address

    – UnholySheep
    1 hour ago






  • 1





    Remember that the default stack size on linux is 10MB and its 1 MB on windows. Also the stack need not be in the same location each time you run your program.

    – drescherjm
    1 hour ago












  • I can't understand why this isn't eligible for tail-call optimization. The invocation of test_func is the last line in the function...

    – cyberbisson
    50 mins ago













  • 1





    You are passing a copy - that has to have an address

    – UnholySheep
    1 hour ago






  • 1





    Remember that the default stack size on linux is 10MB and its 1 MB on windows. Also the stack need not be in the same location each time you run your program.

    – drescherjm
    1 hour ago












  • I can't understand why this isn't eligible for tail-call optimization. The invocation of test_func is the last line in the function...

    – cyberbisson
    50 mins ago








1




1





You are passing a copy - that has to have an address

– UnholySheep
1 hour ago





You are passing a copy - that has to have an address

– UnholySheep
1 hour ago




1




1





Remember that the default stack size on linux is 10MB and its 1 MB on windows. Also the stack need not be in the same location each time you run your program.

– drescherjm
1 hour ago






Remember that the default stack size on linux is 10MB and its 1 MB on windows. Also the stack need not be in the same location each time you run your program.

– drescherjm
1 hour ago














I can't understand why this isn't eligible for tail-call optimization. The invocation of test_func is the last line in the function...

– cyberbisson
50 mins ago






I can't understand why this isn't eligible for tail-call optimization. The invocation of test_func is the last line in the function...

– cyberbisson
50 mins ago













1 Answer
1






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11














Likely address is being placed on the stack and, on your platform, the stack grows downward in memory. See this question about stack growth direction for more.






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    active

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    active

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    11














    Likely address is being placed on the stack and, on your platform, the stack grows downward in memory. See this question about stack growth direction for more.






    share|improve this answer



























      11














      Likely address is being placed on the stack and, on your platform, the stack grows downward in memory. See this question about stack growth direction for more.






      share|improve this answer

























        11












        11








        11







        Likely address is being placed on the stack and, on your platform, the stack grows downward in memory. See this question about stack growth direction for more.






        share|improve this answer













        Likely address is being placed on the stack and, on your platform, the stack grows downward in memory. See this question about stack growth direction for more.







        share|improve this answer












        share|improve this answer



        share|improve this answer










        answered 1 hour ago









        David SchwartzDavid Schwartz

        140k14145232




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