Some basic questions on halt and move in Turing machines“Print 'em all game” for Turing machinesPower of variants of Turing machinesThe control in the Turing MachineThe halting problem of Turing machines in view of enumeration of initial tape configurationsDifficulty in the halting problem for a simple Turing machine with standard enumerations of programs and of initial tape configurationsTuring machine that computes w#w when the input is w?Construct a Turing Machine that recognizes the set $0^2n1^n$For multi-tape Turing machines, can we assume that each tape can be in its own state independently of the other tapes?How would you create a Turing machine that copies a string and prints it to the tape?Turing machine - Transition between two states by more than one condition allowed?
Is this homebrew feat, Beast of Burden, balanced?
Shall I use personal or official e-mail account when registering to external websites for work purpose?
Manga about a female worker who got dragged into another world together with this high school girl and she was just told she's not needed anymore
Is "plugging out" electronic devices an American expression?
Symmetry in quantum mechanics
I’m planning on buying a laser printer but concerned about the life cycle of toner in the machine
Is every set a filtered colimit of finite sets?
How many letters suffice to construct words with no repetition?
Finding files for which a command fails
Could Giant Ground Sloths have been a Good Pack Animal for the Ancient Mayans
New order #4: World
How to manage monthly salary
Landlord wants to switch my lease to a "Land contract" to "get back at the city"
What is GPS' 19 year rollover and does it present a cybersecurity issue?
Is there a way to make member function NOT callable from constructor?
Is repealing the EU Withdrawal Act a precondition of revoking Article 50?
Is domain driven design an anti-SQL pattern?
How do you conduct xenoanthropology after first contact?
Prime joint compound before latex paint?
Can I legally use front facing blue light in the UK?
Copycat chess is back
Is Social Media Science Fiction?
What do you call something that goes against the spirit of the law, but is legal when interpreting the law to the letter?
Are white and non-white police officers equally likely to kill black suspects?
Some basic questions on halt and move in Turing machines
“Print 'em all game” for Turing machinesPower of variants of Turing machinesThe control in the Turing MachineThe halting problem of Turing machines in view of enumeration of initial tape configurationsDifficulty in the halting problem for a simple Turing machine with standard enumerations of programs and of initial tape configurationsTuring machine that computes w#w when the input is w?Construct a Turing Machine that recognizes the set $ngeq 0$For multi-tape Turing machines, can we assume that each tape can be in its own state independently of the other tapes?How would you create a Turing machine that copies a string and prints it to the tape?Turing machine - Transition between two states by more than one condition allowed?
$begingroup$
Im trying to learn about and set up Turing Machines (TMs) the simplest ways using the simplest definite rules. I am using my previous knowledge on simple Cellular Automata to do this. I want to write the computer code, but first I have to get some understanding of the restrictions and possibilities of TMs.
Firstly i define an operation as follows:
Operation (Op)
Do operation based on current color ($C$) and its state ($S$) i.e. $Op(c, s)$:
- replace color $C$ with $0$ or $1$. (at current position of tape head) move
- tape-head (change its position).
- change state $S$ with $0$ or $1$ (at new position).
For each operation:
In general does a TM only have only one halting-operation?
(i.e. can only one operation promote the halting or can more than one operation do that?).Can the tape-head also stop at a fixed position? (i.e. not move its head).
Instead of the rules $0$ (move left) and $1$ (move right), it can also $2$ (not move anywhere) or even jump two units to the left or right?
My last question is basically the same as the last question..
- Can the tape-head move more than one unit to the left or right?
The reason I ask this, is because if there is only one halting state in no more than one operation, the number of rules (in my setup) can be reduced. And if the tape-head can move more than one unit either to the left or right or both my guess is that it can produce more complex outputs. But my questions are concerning what is the limitations of a Turing Machine.
Example
If something was unclear I can try this example:
inp: outp:
Op(0,0) => 110
Op(0,1) => 101
Op(1,0) => 111
Op(1,1) => 001*
Of the output ($b_2b_1b_0$), where the first bit ($b_0$) represent the tapehead-move direction, $b_1$ represents the new state, and $b_0$ represents the changed color.
The asterisk shows that a halting operation should be performed.
The first question I asked wether there was possible to have more than one halting operation in a TM. Basically I ask wether I can have two or more asterisks like this, or if its not allowed:
inp: outp:
Op(0,0) => 110
Op(0,1) => 101
Op(1,0) => 111*
Op(1,1) => 001*
Recap
So can more than one operation perform the halting operation?
Can we move the tape head more than one unit to the left or right, or can it stand still?
turing-machines automata
$endgroup$
add a comment |
$begingroup$
Im trying to learn about and set up Turing Machines (TMs) the simplest ways using the simplest definite rules. I am using my previous knowledge on simple Cellular Automata to do this. I want to write the computer code, but first I have to get some understanding of the restrictions and possibilities of TMs.
Firstly i define an operation as follows:
Operation (Op)
Do operation based on current color ($C$) and its state ($S$) i.e. $Op(c, s)$:
- replace color $C$ with $0$ or $1$. (at current position of tape head) move
- tape-head (change its position).
- change state $S$ with $0$ or $1$ (at new position).
For each operation:
In general does a TM only have only one halting-operation?
(i.e. can only one operation promote the halting or can more than one operation do that?).Can the tape-head also stop at a fixed position? (i.e. not move its head).
Instead of the rules $0$ (move left) and $1$ (move right), it can also $2$ (not move anywhere) or even jump two units to the left or right?
My last question is basically the same as the last question..
- Can the tape-head move more than one unit to the left or right?
The reason I ask this, is because if there is only one halting state in no more than one operation, the number of rules (in my setup) can be reduced. And if the tape-head can move more than one unit either to the left or right or both my guess is that it can produce more complex outputs. But my questions are concerning what is the limitations of a Turing Machine.
Example
If something was unclear I can try this example:
inp: outp:
Op(0,0) => 110
Op(0,1) => 101
Op(1,0) => 111
Op(1,1) => 001*
Of the output ($b_2b_1b_0$), where the first bit ($b_0$) represent the tapehead-move direction, $b_1$ represents the new state, and $b_0$ represents the changed color.
The asterisk shows that a halting operation should be performed.
The first question I asked wether there was possible to have more than one halting operation in a TM. Basically I ask wether I can have two or more asterisks like this, or if its not allowed:
inp: outp:
Op(0,0) => 110
Op(0,1) => 101
Op(1,0) => 111*
Op(1,1) => 001*
Recap
So can more than one operation perform the halting operation?
Can we move the tape head more than one unit to the left or right, or can it stand still?
turing-machines automata
$endgroup$
$begingroup$
You can define your Turing machine model in whichever reasonable way you want, as long as the resulting model is equal in power to a standard Turing machine.
$endgroup$
– Yuval Filmus
9 hours ago
1
$begingroup$
If you are interested in a specific model of Turing machines, then you'll have to specify your model, and then you'll likely be able to answer these questions on your own.
$endgroup$
– Yuval Filmus
9 hours ago
$begingroup$
Thanks, but where can I find info on a standard Turing machine? Was my above descriptions close?
$endgroup$
– Natural Number Guy
9 hours ago
3
$begingroup$
There is no single standard model of a Turing machine. You can find (similar but not identical) definitions on Wikipedia and in any number of textbooks.
$endgroup$
– Yuval Filmus
9 hours ago
add a comment |
$begingroup$
Im trying to learn about and set up Turing Machines (TMs) the simplest ways using the simplest definite rules. I am using my previous knowledge on simple Cellular Automata to do this. I want to write the computer code, but first I have to get some understanding of the restrictions and possibilities of TMs.
Firstly i define an operation as follows:
Operation (Op)
Do operation based on current color ($C$) and its state ($S$) i.e. $Op(c, s)$:
- replace color $C$ with $0$ or $1$. (at current position of tape head) move
- tape-head (change its position).
- change state $S$ with $0$ or $1$ (at new position).
For each operation:
In general does a TM only have only one halting-operation?
(i.e. can only one operation promote the halting or can more than one operation do that?).Can the tape-head also stop at a fixed position? (i.e. not move its head).
Instead of the rules $0$ (move left) and $1$ (move right), it can also $2$ (not move anywhere) or even jump two units to the left or right?
My last question is basically the same as the last question..
- Can the tape-head move more than one unit to the left or right?
The reason I ask this, is because if there is only one halting state in no more than one operation, the number of rules (in my setup) can be reduced. And if the tape-head can move more than one unit either to the left or right or both my guess is that it can produce more complex outputs. But my questions are concerning what is the limitations of a Turing Machine.
Example
If something was unclear I can try this example:
inp: outp:
Op(0,0) => 110
Op(0,1) => 101
Op(1,0) => 111
Op(1,1) => 001*
Of the output ($b_2b_1b_0$), where the first bit ($b_0$) represent the tapehead-move direction, $b_1$ represents the new state, and $b_0$ represents the changed color.
The asterisk shows that a halting operation should be performed.
The first question I asked wether there was possible to have more than one halting operation in a TM. Basically I ask wether I can have two or more asterisks like this, or if its not allowed:
inp: outp:
Op(0,0) => 110
Op(0,1) => 101
Op(1,0) => 111*
Op(1,1) => 001*
Recap
So can more than one operation perform the halting operation?
Can we move the tape head more than one unit to the left or right, or can it stand still?
turing-machines automata
$endgroup$
Im trying to learn about and set up Turing Machines (TMs) the simplest ways using the simplest definite rules. I am using my previous knowledge on simple Cellular Automata to do this. I want to write the computer code, but first I have to get some understanding of the restrictions and possibilities of TMs.
Firstly i define an operation as follows:
Operation (Op)
Do operation based on current color ($C$) and its state ($S$) i.e. $Op(c, s)$:
- replace color $C$ with $0$ or $1$. (at current position of tape head) move
- tape-head (change its position).
- change state $S$ with $0$ or $1$ (at new position).
For each operation:
In general does a TM only have only one halting-operation?
(i.e. can only one operation promote the halting or can more than one operation do that?).Can the tape-head also stop at a fixed position? (i.e. not move its head).
Instead of the rules $0$ (move left) and $1$ (move right), it can also $2$ (not move anywhere) or even jump two units to the left or right?
My last question is basically the same as the last question..
- Can the tape-head move more than one unit to the left or right?
The reason I ask this, is because if there is only one halting state in no more than one operation, the number of rules (in my setup) can be reduced. And if the tape-head can move more than one unit either to the left or right or both my guess is that it can produce more complex outputs. But my questions are concerning what is the limitations of a Turing Machine.
Example
If something was unclear I can try this example:
inp: outp:
Op(0,0) => 110
Op(0,1) => 101
Op(1,0) => 111
Op(1,1) => 001*
Of the output ($b_2b_1b_0$), where the first bit ($b_0$) represent the tapehead-move direction, $b_1$ represents the new state, and $b_0$ represents the changed color.
The asterisk shows that a halting operation should be performed.
The first question I asked wether there was possible to have more than one halting operation in a TM. Basically I ask wether I can have two or more asterisks like this, or if its not allowed:
inp: outp:
Op(0,0) => 110
Op(0,1) => 101
Op(1,0) => 111*
Op(1,1) => 001*
Recap
So can more than one operation perform the halting operation?
Can we move the tape head more than one unit to the left or right, or can it stand still?
turing-machines automata
turing-machines automata
asked 9 hours ago
Natural Number GuyNatural Number Guy
1154
1154
$begingroup$
You can define your Turing machine model in whichever reasonable way you want, as long as the resulting model is equal in power to a standard Turing machine.
$endgroup$
– Yuval Filmus
9 hours ago
1
$begingroup$
If you are interested in a specific model of Turing machines, then you'll have to specify your model, and then you'll likely be able to answer these questions on your own.
$endgroup$
– Yuval Filmus
9 hours ago
$begingroup$
Thanks, but where can I find info on a standard Turing machine? Was my above descriptions close?
$endgroup$
– Natural Number Guy
9 hours ago
3
$begingroup$
There is no single standard model of a Turing machine. You can find (similar but not identical) definitions on Wikipedia and in any number of textbooks.
$endgroup$
– Yuval Filmus
9 hours ago
add a comment |
$begingroup$
You can define your Turing machine model in whichever reasonable way you want, as long as the resulting model is equal in power to a standard Turing machine.
$endgroup$
– Yuval Filmus
9 hours ago
1
$begingroup$
If you are interested in a specific model of Turing machines, then you'll have to specify your model, and then you'll likely be able to answer these questions on your own.
$endgroup$
– Yuval Filmus
9 hours ago
$begingroup$
Thanks, but where can I find info on a standard Turing machine? Was my above descriptions close?
$endgroup$
– Natural Number Guy
9 hours ago
3
$begingroup$
There is no single standard model of a Turing machine. You can find (similar but not identical) definitions on Wikipedia and in any number of textbooks.
$endgroup$
– Yuval Filmus
9 hours ago
$begingroup$
You can define your Turing machine model in whichever reasonable way you want, as long as the resulting model is equal in power to a standard Turing machine.
$endgroup$
– Yuval Filmus
9 hours ago
$begingroup$
You can define your Turing machine model in whichever reasonable way you want, as long as the resulting model is equal in power to a standard Turing machine.
$endgroup$
– Yuval Filmus
9 hours ago
1
1
$begingroup$
If you are interested in a specific model of Turing machines, then you'll have to specify your model, and then you'll likely be able to answer these questions on your own.
$endgroup$
– Yuval Filmus
9 hours ago
$begingroup$
If you are interested in a specific model of Turing machines, then you'll have to specify your model, and then you'll likely be able to answer these questions on your own.
$endgroup$
– Yuval Filmus
9 hours ago
$begingroup$
Thanks, but where can I find info on a standard Turing machine? Was my above descriptions close?
$endgroup$
– Natural Number Guy
9 hours ago
$begingroup$
Thanks, but where can I find info on a standard Turing machine? Was my above descriptions close?
$endgroup$
– Natural Number Guy
9 hours ago
3
3
$begingroup$
There is no single standard model of a Turing machine. You can find (similar but not identical) definitions on Wikipedia and in any number of textbooks.
$endgroup$
– Yuval Filmus
9 hours ago
$begingroup$
There is no single standard model of a Turing machine. You can find (similar but not identical) definitions on Wikipedia and in any number of textbooks.
$endgroup$
– Yuval Filmus
9 hours ago
add a comment |
1 Answer
1
active
oldest
votes
$begingroup$
To answer any kind of question like this, you need to choose one of the standard definitions of Turing machines (there are several but they're all essentially the same) and prove that adding the feature you want doesn't increase the computational power. You do that by showing how to simulate the feature using the standard machine.
- In general does a TM only have only one halting-operation? (i.e. can only one operation promote the halting or can more than one operation do that?).
It doesn't matter. If you want three halting states and I insist that there can be only one, then have three states called $h_1$, $h_2$ and $h_3$ and design the transition function so that, if the machine ever enters one of those, its next transition is to $mathrmHALT$.
- Can the tape-head also stop at a fixed position? (i.e. not move its head). Instead of the rules 0 (move left) and 1 (move right), it can also 2 (not move anywhere) or even jump two units to the left or right?
Again, it doesn't matter. If I insist you must move left or right, you can move one step left and then move back to the right; you can move two steps to the right by moving one step, twice.
- Can the tape-head move more than one unit to the left or right?
Even that doesn't affect things: random-access Turing machines have an "address tape" onto which you can write a number and a special state that causes the head to move straight to the tape cell indexed by that number. Again, same power.
Multiple tapes, inserting and deleting characters, two-dimensional (or more!) tapes. Almost anything you can imagine makes no difference, and proving these things are standard exercises in computation theory textbooks.
$endgroup$
$begingroup$
One more question: What about the Buzzy Beaver TM, does the same rules apply there? Or do they have restricted rules on the movements and halting ops.
$endgroup$
– Natural Number Guy
1 hour ago
$begingroup$
You can ask the busy beaver question for any specific definition of Turing machines. It probably doesn't make a lot of difference to the answer -- it's uncomputable regardless, and the answer to any busy beaver question is "some huge number".
$endgroup$
– David Richerby
21 mins ago
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
return StackExchange.using("mathjaxEditing", function ()
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
);
);
, "mathjax-editing");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "419"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcs.stackexchange.com%2fquestions%2f106651%2fsome-basic-questions-on-halt-and-move-in-turing-machines%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
1 Answer
1
active
oldest
votes
1 Answer
1
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
To answer any kind of question like this, you need to choose one of the standard definitions of Turing machines (there are several but they're all essentially the same) and prove that adding the feature you want doesn't increase the computational power. You do that by showing how to simulate the feature using the standard machine.
- In general does a TM only have only one halting-operation? (i.e. can only one operation promote the halting or can more than one operation do that?).
It doesn't matter. If you want three halting states and I insist that there can be only one, then have three states called $h_1$, $h_2$ and $h_3$ and design the transition function so that, if the machine ever enters one of those, its next transition is to $mathrmHALT$.
- Can the tape-head also stop at a fixed position? (i.e. not move its head). Instead of the rules 0 (move left) and 1 (move right), it can also 2 (not move anywhere) or even jump two units to the left or right?
Again, it doesn't matter. If I insist you must move left or right, you can move one step left and then move back to the right; you can move two steps to the right by moving one step, twice.
- Can the tape-head move more than one unit to the left or right?
Even that doesn't affect things: random-access Turing machines have an "address tape" onto which you can write a number and a special state that causes the head to move straight to the tape cell indexed by that number. Again, same power.
Multiple tapes, inserting and deleting characters, two-dimensional (or more!) tapes. Almost anything you can imagine makes no difference, and proving these things are standard exercises in computation theory textbooks.
$endgroup$
$begingroup$
One more question: What about the Buzzy Beaver TM, does the same rules apply there? Or do they have restricted rules on the movements and halting ops.
$endgroup$
– Natural Number Guy
1 hour ago
$begingroup$
You can ask the busy beaver question for any specific definition of Turing machines. It probably doesn't make a lot of difference to the answer -- it's uncomputable regardless, and the answer to any busy beaver question is "some huge number".
$endgroup$
– David Richerby
21 mins ago
add a comment |
$begingroup$
To answer any kind of question like this, you need to choose one of the standard definitions of Turing machines (there are several but they're all essentially the same) and prove that adding the feature you want doesn't increase the computational power. You do that by showing how to simulate the feature using the standard machine.
- In general does a TM only have only one halting-operation? (i.e. can only one operation promote the halting or can more than one operation do that?).
It doesn't matter. If you want three halting states and I insist that there can be only one, then have three states called $h_1$, $h_2$ and $h_3$ and design the transition function so that, if the machine ever enters one of those, its next transition is to $mathrmHALT$.
- Can the tape-head also stop at a fixed position? (i.e. not move its head). Instead of the rules 0 (move left) and 1 (move right), it can also 2 (not move anywhere) or even jump two units to the left or right?
Again, it doesn't matter. If I insist you must move left or right, you can move one step left and then move back to the right; you can move two steps to the right by moving one step, twice.
- Can the tape-head move more than one unit to the left or right?
Even that doesn't affect things: random-access Turing machines have an "address tape" onto which you can write a number and a special state that causes the head to move straight to the tape cell indexed by that number. Again, same power.
Multiple tapes, inserting and deleting characters, two-dimensional (or more!) tapes. Almost anything you can imagine makes no difference, and proving these things are standard exercises in computation theory textbooks.
$endgroup$
$begingroup$
One more question: What about the Buzzy Beaver TM, does the same rules apply there? Or do they have restricted rules on the movements and halting ops.
$endgroup$
– Natural Number Guy
1 hour ago
$begingroup$
You can ask the busy beaver question for any specific definition of Turing machines. It probably doesn't make a lot of difference to the answer -- it's uncomputable regardless, and the answer to any busy beaver question is "some huge number".
$endgroup$
– David Richerby
21 mins ago
add a comment |
$begingroup$
To answer any kind of question like this, you need to choose one of the standard definitions of Turing machines (there are several but they're all essentially the same) and prove that adding the feature you want doesn't increase the computational power. You do that by showing how to simulate the feature using the standard machine.
- In general does a TM only have only one halting-operation? (i.e. can only one operation promote the halting or can more than one operation do that?).
It doesn't matter. If you want three halting states and I insist that there can be only one, then have three states called $h_1$, $h_2$ and $h_3$ and design the transition function so that, if the machine ever enters one of those, its next transition is to $mathrmHALT$.
- Can the tape-head also stop at a fixed position? (i.e. not move its head). Instead of the rules 0 (move left) and 1 (move right), it can also 2 (not move anywhere) or even jump two units to the left or right?
Again, it doesn't matter. If I insist you must move left or right, you can move one step left and then move back to the right; you can move two steps to the right by moving one step, twice.
- Can the tape-head move more than one unit to the left or right?
Even that doesn't affect things: random-access Turing machines have an "address tape" onto which you can write a number and a special state that causes the head to move straight to the tape cell indexed by that number. Again, same power.
Multiple tapes, inserting and deleting characters, two-dimensional (or more!) tapes. Almost anything you can imagine makes no difference, and proving these things are standard exercises in computation theory textbooks.
$endgroup$
To answer any kind of question like this, you need to choose one of the standard definitions of Turing machines (there are several but they're all essentially the same) and prove that adding the feature you want doesn't increase the computational power. You do that by showing how to simulate the feature using the standard machine.
- In general does a TM only have only one halting-operation? (i.e. can only one operation promote the halting or can more than one operation do that?).
It doesn't matter. If you want three halting states and I insist that there can be only one, then have three states called $h_1$, $h_2$ and $h_3$ and design the transition function so that, if the machine ever enters one of those, its next transition is to $mathrmHALT$.
- Can the tape-head also stop at a fixed position? (i.e. not move its head). Instead of the rules 0 (move left) and 1 (move right), it can also 2 (not move anywhere) or even jump two units to the left or right?
Again, it doesn't matter. If I insist you must move left or right, you can move one step left and then move back to the right; you can move two steps to the right by moving one step, twice.
- Can the tape-head move more than one unit to the left or right?
Even that doesn't affect things: random-access Turing machines have an "address tape" onto which you can write a number and a special state that causes the head to move straight to the tape cell indexed by that number. Again, same power.
Multiple tapes, inserting and deleting characters, two-dimensional (or more!) tapes. Almost anything you can imagine makes no difference, and proving these things are standard exercises in computation theory textbooks.
answered 8 hours ago
David RicherbyDavid Richerby
69.8k15106195
69.8k15106195
$begingroup$
One more question: What about the Buzzy Beaver TM, does the same rules apply there? Or do they have restricted rules on the movements and halting ops.
$endgroup$
– Natural Number Guy
1 hour ago
$begingroup$
You can ask the busy beaver question for any specific definition of Turing machines. It probably doesn't make a lot of difference to the answer -- it's uncomputable regardless, and the answer to any busy beaver question is "some huge number".
$endgroup$
– David Richerby
21 mins ago
add a comment |
$begingroup$
One more question: What about the Buzzy Beaver TM, does the same rules apply there? Or do they have restricted rules on the movements and halting ops.
$endgroup$
– Natural Number Guy
1 hour ago
$begingroup$
You can ask the busy beaver question for any specific definition of Turing machines. It probably doesn't make a lot of difference to the answer -- it's uncomputable regardless, and the answer to any busy beaver question is "some huge number".
$endgroup$
– David Richerby
21 mins ago
$begingroup$
One more question: What about the Buzzy Beaver TM, does the same rules apply there? Or do they have restricted rules on the movements and halting ops.
$endgroup$
– Natural Number Guy
1 hour ago
$begingroup$
One more question: What about the Buzzy Beaver TM, does the same rules apply there? Or do they have restricted rules on the movements and halting ops.
$endgroup$
– Natural Number Guy
1 hour ago
$begingroup$
You can ask the busy beaver question for any specific definition of Turing machines. It probably doesn't make a lot of difference to the answer -- it's uncomputable regardless, and the answer to any busy beaver question is "some huge number".
$endgroup$
– David Richerby
21 mins ago
$begingroup$
You can ask the busy beaver question for any specific definition of Turing machines. It probably doesn't make a lot of difference to the answer -- it's uncomputable regardless, and the answer to any busy beaver question is "some huge number".
$endgroup$
– David Richerby
21 mins ago
add a comment |
Thanks for contributing an answer to Computer Science Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fcs.stackexchange.com%2fquestions%2f106651%2fsome-basic-questions-on-halt-and-move-in-turing-machines%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
$begingroup$
You can define your Turing machine model in whichever reasonable way you want, as long as the resulting model is equal in power to a standard Turing machine.
$endgroup$
– Yuval Filmus
9 hours ago
1
$begingroup$
If you are interested in a specific model of Turing machines, then you'll have to specify your model, and then you'll likely be able to answer these questions on your own.
$endgroup$
– Yuval Filmus
9 hours ago
$begingroup$
Thanks, but where can I find info on a standard Turing machine? Was my above descriptions close?
$endgroup$
– Natural Number Guy
9 hours ago
3
$begingroup$
There is no single standard model of a Turing machine. You can find (similar but not identical) definitions on Wikipedia and in any number of textbooks.
$endgroup$
– Yuval Filmus
9 hours ago