How to reverse every other sublist of a list? The 2019 Stack Overflow Developer Survey Results Are InHow can the lowest non-zero value in a nested list be found and its position in the sublist returned?Comparing elements of the $n^textth$ sublist in a ragged list with the $n^textth$ member of a sequenceSublist inside simple listHow to split list into disjoint lists?Selecting every last element of a nested listAdd elements of one list to sublists of another listEliminating elements from sublists under a global conditionRemove the right sublistList manipulation - adding last element of sublist to each sublistHow to partition a 1D list according to specified lengths?
"What time...?" or "At what time...?" - what is more grammatically correct?
Supports in 3d printing
Carnot-Caratheodory metric
is usb on wall sockets live all the time with out switches off
What are the advantages and disadvantages of running one shots compared to campaigns?
Output the Arecibo Message
How can I create a character who can assume the widest possible range of creature sizes?
Spanish for "widget"
Extreme, unacceptable situation and I can't attend work tomorrow morning
Patience, young "Padovan"
Is it possible for the two major parties in the UK to form a coalition with each other instead of a much smaller party?
Where does the "burst of radiance" from Holy Weapon originate?
description of papers that have not been submitted to a venue?
What is the meaning of Triage in Cybersec world?
What are the motivations for publishing new editions of an existing textbook, beyond new discoveries in a field?
Why is it "Tumoren" and not "Tumore"?
Geography at the pixel level
Can I write a for loop that iterates over both collections and arrays?
Time travel alters history but people keep saying nothing's changed
A poker game description that does not feel gimmicky
Which Sci-Fi work first showed weapon of galactic-scale mass destruction?
What does "sndry explns" mean in one of the Hitchhiker's guide books?
Pristine Bit Checking
Is the gradient of the self-intersections of a curve zero?
How to reverse every other sublist of a list?
The 2019 Stack Overflow Developer Survey Results Are InHow can the lowest non-zero value in a nested list be found and its position in the sublist returned?Comparing elements of the $n^textth$ sublist in a ragged list with the $n^textth$ member of a sequenceSublist inside simple listHow to split list into disjoint lists?Selecting every last element of a nested listAdd elements of one list to sublists of another listEliminating elements from sublists under a global conditionRemove the right sublistList manipulation - adding last element of sublist to each sublistHow to partition a 1D list according to specified lengths?
$begingroup$
I have a list with sublists list = 1, 2, 3, 4, 5, 6, 7, 8. I would like to reverse every other sublist, starting from the second one. The result would look like result = 1, 2, 4, 3, 5, 6, 8, 7. What would be a simple way to do this?
list-manipulation
asked 1 hour ago
nanjunnanjun
43229
$endgroup$
add a comment |
$begingroup$
I have a list with sublists list = 1, 2, 3, 4, 5, 6, 7, 8. I would like to reverse every other sublist, starting from the second one. The result would look like result = 1, 2, 4, 3, 5, 6, 8, 7. What would be a simple way to do this?
list-manipulation
asked 1 hour ago
nanjunnanjun
43229
$endgroup$
add a comment |
$begingroup$
I have a list with sublists list = 1, 2, 3, 4, 5, 6, 7, 8. I would like to reverse every other sublist, starting from the second one. The result would look like result = 1, 2, 4, 3, 5, 6, 8, 7. What would be a simple way to do this?
list-manipulation
asked 1 hour ago
nanjunnanjun
43229
$endgroup$
I have a list with sublists list = 1, 2, 3, 4, 5, 6, 7, 8. I would like to reverse every other sublist, starting from the second one. The result would look like result = 1, 2, 4, 3, 5, 6, 8, 7. What would be a simple way to do this?
list-manipulation
list-manipulation
asked 1 hour ago
nanjunnanjun
43229
asked 1 hour ago
nanjunnanjun
43229
asked 1 hour ago
nanjunnanjun
43229
asked 1 hour ago
nanjunnanjun
43229
asked 1 hour ago
nanjunnanjun
43229
43229
add a comment |
add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
Use MapAt, which accepts the same syntax as Part:
MapAt[Reverse, list, 2 ;; ;; 2]
(* 1, 2, 4, 3, 5, 6, 8, 7 *)
answered 1 hour ago
marchmarch
17.5k22769
$endgroup$
add a comment |
$begingroup$
Using Part and Span might not seem overly elegant but it is fast:
list = RandomReal[-1, 1, 100000, 10];
a = MapAt[Reverse, list, 2 ;; ;; 2]; // RepeatedTiming // First
b = ReplacePart[list, i_?EvenQ :> Reverse@list[[i]]]; // RepeatedTiming // First
c = Module[result = list,
result[[2 ;; ;; 2]] =
list[[2 ;; ;; 2, -1 ;; 1 ;; -1]];
result
]; // RepeatedTiming // First
a == b == c
0.11
0.317
0.0036
True
answered 30 mins ago
Henrik SchumacherHenrik Schumacher
59.6k582166
$endgroup$
add a comment |
$begingroup$
Another method is to use ReplacePart:
ReplacePart[1, 2, 3, 4, 5, 6, 7, 8,
i_ ? EvenQ :> Reverse@list[[i]]
]
(* 1,2,4,3,5,6,8,7 *)
answered 40 mins ago
Jason B.Jason B.
48.9k389196
$endgroup$
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
return StackExchange.using("mathjaxEditing", function ()
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
);
);
, "mathjax-editing");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "387"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f194901%2fhow-to-reverse-every-other-sublist-of-a-list%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Use MapAt, which accepts the same syntax as Part:
MapAt[Reverse, list, 2 ;; ;; 2]
(* 1, 2, 4, 3, 5, 6, 8, 7 *)
answered 1 hour ago
marchmarch
17.5k22769
$endgroup$
add a comment |
$begingroup$
Use MapAt, which accepts the same syntax as Part:
MapAt[Reverse, list, 2 ;; ;; 2]
(* 1, 2, 4, 3, 5, 6, 8, 7 *)
answered 1 hour ago
marchmarch
17.5k22769
$endgroup$
add a comment |
$begingroup$
Use MapAt, which accepts the same syntax as Part:
MapAt[Reverse, list, 2 ;; ;; 2]
(* 1, 2, 4, 3, 5, 6, 8, 7 *)
answered 1 hour ago
marchmarch
17.5k22769
$endgroup$
Use MapAt, which accepts the same syntax as Part:
MapAt[Reverse, list, 2 ;; ;; 2]
(* 1, 2, 4, 3, 5, 6, 8, 7 *)
answered 1 hour ago
marchmarch
17.5k22769
answered 1 hour ago
marchmarch
17.5k22769
answered 1 hour ago
marchmarch
17.5k22769
answered 1 hour ago
marchmarch
17.5k22769
17.5k22769
add a comment |
add a comment |
$begingroup$
Using Part and Span might not seem overly elegant but it is fast:
list = RandomReal[-1, 1, 100000, 10];
a = MapAt[Reverse, list, 2 ;; ;; 2]; // RepeatedTiming // First
b = ReplacePart[list, i_?EvenQ :> Reverse@list[[i]]]; // RepeatedTiming // First
c = Module[result = list,
result[[2 ;; ;; 2]] =
list[[2 ;; ;; 2, -1 ;; 1 ;; -1]];
result
]; // RepeatedTiming // First
a == b == c
0.11
0.317
0.0036
True
answered 30 mins ago
Henrik SchumacherHenrik Schumacher
59.6k582166
$endgroup$
add a comment |
$begingroup$
Using Part and Span might not seem overly elegant but it is fast:
list = RandomReal[-1, 1, 100000, 10];
a = MapAt[Reverse, list, 2 ;; ;; 2]; // RepeatedTiming // First
b = ReplacePart[list, i_?EvenQ :> Reverse@list[[i]]]; // RepeatedTiming // First
c = Module[result = list,
result[[2 ;; ;; 2]] =
list[[2 ;; ;; 2, -1 ;; 1 ;; -1]];
result
]; // RepeatedTiming // First
a == b == c
0.11
0.317
0.0036
True
answered 30 mins ago
Henrik SchumacherHenrik Schumacher
59.6k582166
$endgroup$
add a comment |
$begingroup$
Using Part and Span might not seem overly elegant but it is fast:
list = RandomReal[-1, 1, 100000, 10];
a = MapAt[Reverse, list, 2 ;; ;; 2]; // RepeatedTiming // First
b = ReplacePart[list, i_?EvenQ :> Reverse@list[[i]]]; // RepeatedTiming // First
c = Module[result = list,
result[[2 ;; ;; 2]] =
list[[2 ;; ;; 2, -1 ;; 1 ;; -1]];
result
]; // RepeatedTiming // First
a == b == c
0.11
0.317
0.0036
True
answered 30 mins ago
Henrik SchumacherHenrik Schumacher
59.6k582166
$endgroup$
Using Part and Span might not seem overly elegant but it is fast:
list = RandomReal[-1, 1, 100000, 10];
a = MapAt[Reverse, list, 2 ;; ;; 2]; // RepeatedTiming // First
b = ReplacePart[list, i_?EvenQ :> Reverse@list[[i]]]; // RepeatedTiming // First
c = Module[result = list,
result[[2 ;; ;; 2]] =
list[[2 ;; ;; 2, -1 ;; 1 ;; -1]];
result
]; // RepeatedTiming // First
a == b == c
0.11
0.317
0.0036
True
answered 30 mins ago
Henrik SchumacherHenrik Schumacher
59.6k582166
answered 30 mins ago
Henrik SchumacherHenrik Schumacher
59.6k582166
answered 30 mins ago
Henrik SchumacherHenrik Schumacher
59.6k582166
answered 30 mins ago
Henrik SchumacherHenrik Schumacher
59.6k582166
59.6k582166
add a comment |
add a comment |
$begingroup$
Another method is to use ReplacePart:
ReplacePart[1, 2, 3, 4, 5, 6, 7, 8,
i_ ? EvenQ :> Reverse@list[[i]]
]
(* 1,2,4,3,5,6,8,7 *)
answered 40 mins ago
Jason B.Jason B.
48.9k389196
$endgroup$
add a comment |
$begingroup$
Another method is to use ReplacePart:
ReplacePart[1, 2, 3, 4, 5, 6, 7, 8,
i_ ? EvenQ :> Reverse@list[[i]]
]
(* 1,2,4,3,5,6,8,7 *)
answered 40 mins ago
Jason B.Jason B.
48.9k389196
$endgroup$
add a comment |
$begingroup$
Another method is to use ReplacePart:
ReplacePart[1, 2, 3, 4, 5, 6, 7, 8,
i_ ? EvenQ :> Reverse@list[[i]]
]
(* 1,2,4,3,5,6,8,7 *)
answered 40 mins ago
Jason B.Jason B.
48.9k389196
$endgroup$
Another method is to use ReplacePart:
ReplacePart[1, 2, 3, 4, 5, 6, 7, 8,
i_ ? EvenQ :> Reverse@list[[i]]
]
(* 1,2,4,3,5,6,8,7 *)
answered 40 mins ago
Jason B.Jason B.
48.9k389196
answered 40 mins ago
Jason B.Jason B.
48.9k389196
answered 40 mins ago
Jason B.Jason B.
48.9k389196
answered 40 mins ago
Jason B.Jason B.
48.9k389196
48.9k389196
add a comment |
add a comment |
Thanks for contributing an answer to Mathematica Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f194901%2fhow-to-reverse-every-other-sublist-of-a-list%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
