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Mechanism of the formation of peracetic acid



Unicorn Meta Zoo #1: Why another podcast?
Announcing the arrival of Valued Associate #679: Cesar Manara
2019 Moderator Election Q&A - Question CollectionFormation of peracetic acid from acetic acid and hydrogen peroxide and its stability in their presenceIs this the correct mechanism of the formation of the nitronium (NO2+) ion from sodium nitrate and sulfuric acid?Diethyl Ether reaction mechanism1-5 dicarboxylic acid to lactone with SOCl2?Mechanism of substitution reaction with no change in stereochemistryMechanism of Fisher esterification: Does the carboxylic acid gives off OH- or H+?Why does the proton transfer from the oxygen to the nitrogen atom in imine formation not occur through an intramolecular process?NGP mechanism vs the simple carbocation mechanismAcid Catalysed Ring Expansion – Mechanism?Role of solvents in ozonolysis and oz0nolysis of alkynes with waterWhy does Oxygen act as Nucleophile over here?










2












$begingroup$


Wikipedia says that the equilibrium $$ceH2O2 + CH3COOH ⇌ CH3COOOH + H2O$$ occurs. What is its mechanism?

The following is my speculation.



The first possibility is that $ceCH3COOH$ is protonated into $ceCH3CO(OH2)+$ because of the strong acid condition and then turns into $ceCH3C+O$. Because the oxygen atom in $ceH2O2$ is electron rich, it will bond with the carbon atom with positive charge to form $ceCH3C(=O)O(OH+)H$ and then peracetic acid is formed by deprotonation.

The second one is that the oxygen atom in $ceH2O2$ attacks the carbon atom in $ceMeCOOH$, then the $ceOH$ in $ceCOOH$ and
one of the $ce H$ in $ce H2O2$ leave.



Is the mechanism above right or not? If it is not, what's the correct one?



P.S. (this question does not answer my question)










share|improve this question







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$endgroup$
















    2












    $begingroup$


    Wikipedia says that the equilibrium $$ceH2O2 + CH3COOH ⇌ CH3COOOH + H2O$$ occurs. What is its mechanism?

    The following is my speculation.



    The first possibility is that $ceCH3COOH$ is protonated into $ceCH3CO(OH2)+$ because of the strong acid condition and then turns into $ceCH3C+O$. Because the oxygen atom in $ceH2O2$ is electron rich, it will bond with the carbon atom with positive charge to form $ceCH3C(=O)O(OH+)H$ and then peracetic acid is formed by deprotonation.

    The second one is that the oxygen atom in $ceH2O2$ attacks the carbon atom in $ceMeCOOH$, then the $ceOH$ in $ceCOOH$ and
    one of the $ce H$ in $ce H2O2$ leave.



    Is the mechanism above right or not? If it is not, what's the correct one?



    P.S. (this question does not answer my question)










    share|improve this question







    New contributor




    Kemono Chen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$














      2












      2








      2





      $begingroup$


      Wikipedia says that the equilibrium $$ceH2O2 + CH3COOH ⇌ CH3COOOH + H2O$$ occurs. What is its mechanism?

      The following is my speculation.



      The first possibility is that $ceCH3COOH$ is protonated into $ceCH3CO(OH2)+$ because of the strong acid condition and then turns into $ceCH3C+O$. Because the oxygen atom in $ceH2O2$ is electron rich, it will bond with the carbon atom with positive charge to form $ceCH3C(=O)O(OH+)H$ and then peracetic acid is formed by deprotonation.

      The second one is that the oxygen atom in $ceH2O2$ attacks the carbon atom in $ceMeCOOH$, then the $ceOH$ in $ceCOOH$ and
      one of the $ce H$ in $ce H2O2$ leave.



      Is the mechanism above right or not? If it is not, what's the correct one?



      P.S. (this question does not answer my question)










      share|improve this question







      New contributor




      Kemono Chen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      Wikipedia says that the equilibrium $$ceH2O2 + CH3COOH ⇌ CH3COOOH + H2O$$ occurs. What is its mechanism?

      The following is my speculation.



      The first possibility is that $ceCH3COOH$ is protonated into $ceCH3CO(OH2)+$ because of the strong acid condition and then turns into $ceCH3C+O$. Because the oxygen atom in $ceH2O2$ is electron rich, it will bond with the carbon atom with positive charge to form $ceCH3C(=O)O(OH+)H$ and then peracetic acid is formed by deprotonation.

      The second one is that the oxygen atom in $ceH2O2$ attacks the carbon atom in $ceMeCOOH$, then the $ceOH$ in $ceCOOH$ and
      one of the $ce H$ in $ce H2O2$ leave.



      Is the mechanism above right or not? If it is not, what's the correct one?



      P.S. (this question does not answer my question)







      organic-chemistry reaction-mechanism






      share|improve this question







      New contributor




      Kemono Chen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      share|improve this question







      New contributor




      Kemono Chen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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      share|improve this question






      New contributor




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      asked 1 hour ago









      Kemono ChenKemono Chen

      1134




      1134




      New contributor




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      New contributor





      Kemono Chen is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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          1 Answer
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          $begingroup$

          You are not too far off. It is somewhat of a mixture of the two mechanisms you proposed. The carbonyl oxygen is much more basic than the non-carbonyl oxygen and will be protonated preferentially. Then hydrogen peroxide can attack, and once the tetrahedral intermediate collapses, deprotonation yields peracetic acid.



          enter image description here






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            $begingroup$

            You are not too far off. It is somewhat of a mixture of the two mechanisms you proposed. The carbonyl oxygen is much more basic than the non-carbonyl oxygen and will be protonated preferentially. Then hydrogen peroxide can attack, and once the tetrahedral intermediate collapses, deprotonation yields peracetic acid.



            enter image description here






            share|improve this answer









            $endgroup$

















              2












              $begingroup$

              You are not too far off. It is somewhat of a mixture of the two mechanisms you proposed. The carbonyl oxygen is much more basic than the non-carbonyl oxygen and will be protonated preferentially. Then hydrogen peroxide can attack, and once the tetrahedral intermediate collapses, deprotonation yields peracetic acid.



              enter image description here






              share|improve this answer









              $endgroup$















                2












                2








                2





                $begingroup$

                You are not too far off. It is somewhat of a mixture of the two mechanisms you proposed. The carbonyl oxygen is much more basic than the non-carbonyl oxygen and will be protonated preferentially. Then hydrogen peroxide can attack, and once the tetrahedral intermediate collapses, deprotonation yields peracetic acid.



                enter image description here






                share|improve this answer









                $endgroup$



                You are not too far off. It is somewhat of a mixture of the two mechanisms you proposed. The carbonyl oxygen is much more basic than the non-carbonyl oxygen and will be protonated preferentially. Then hydrogen peroxide can attack, and once the tetrahedral intermediate collapses, deprotonation yields peracetic acid.



                enter image description here







                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 1 hour ago









                ringoringo

                20.3k559112




                20.3k559112




















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