How do you solve the twins Paradox? Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 23, 2019 at 00:00UTC (8:00pm US/Eastern) 2019 Moderator Election Q&A - Question CollectionWhat is the proper way to explain the twin paradox?Is time dilation an illusion? Variation on the twins paradoxTwin paradox caused by gravitational difference in spaceTwins paradox questionTheory of relativity paradox?Explanation for a much simpler version of the twin paradox?What is the proper way to explain the twin paradox?The twin paradox in a universe with a torus topologyTwin Paradox on steroids - who would be older?The twin Paradox, What if they never meet and they are observed by an outside observer?How do we explain this new take on the old Twins Paradox?

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How do you solve the twins Paradox?



Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 23, 2019 at 00:00UTC (8:00pm US/Eastern)
2019 Moderator Election Q&A - Question CollectionWhat is the proper way to explain the twin paradox?Is time dilation an illusion? Variation on the twins paradoxTwin paradox caused by gravitational difference in spaceTwins paradox questionTheory of relativity paradox?Explanation for a much simpler version of the twin paradox?What is the proper way to explain the twin paradox?The twin paradox in a universe with a torus topologyTwin Paradox on steroids - who would be older?The twin Paradox, What if they never meet and they are observed by an outside observer?How do we explain this new take on the old Twins Paradox?










1












$begingroup$


I'm a beginner physics student only studying elementary AP-level physics and calculus, so when I came across the conceptual basis of the twins paradox I was, of course curious. People often explain the paradox away by explaining how the symmetry from each perspective is broken, without satisfactorily illustrating why. Before I ask my question I want to explain from my understanding-



So you have a twin on earth who understands that his twin is on a spaceship accelerating away arbitrarily close to the speed of light then returning home. He accelerates away and comes back, and I understand why the twin on the spaceship believes the other is older- Because on a spacetime diagram, we recognize that the axis flips and the twin on the ship understands that the relativistic affect on him will result in a difference.



So my question is: How do both observers figure out WHO is accelerating to begin with? To illustrate my problem with the paradox, I instead imagine two twins floating in space 1 meter apart in a vacuum, until one sees the other accelerate to near light speed. If we assume that the twins will return to their initial position at 1 meter apart, only ONE of them will age. The problem is figuring out who?



This is because: If twin A assumes he is stationary, and twin B assumes he is accelerating, then they can work out the respective maths. But what happens if both assume that they are accelerating, or that both are stationary? This is what results in the apparent paradox isn't it? So the real question should be: How do we know who is objectively accelerating?










share|cite|improve this question









New contributor




Roberto Singer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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$endgroup$







  • 3




    $begingroup$
    Possible duplicate of What is the proper way to explain the twin paradox?
    $endgroup$
    – StephenG
    3 hours ago











  • $begingroup$
    No, these answers all assume from the getgo that one twin is accelerating and knows he is accelerating, and the other twin is stationary and knows he is stationary, and both observers agree on who is what. If all you know is that the other observer is accelerating, how do you measure which of the twins is really experiencing acceleration? The paradox arises when each twin assumes he is stationary/accelerating. If they agree on which is which its easy to make the calculations, but how can they objectively measure whose frame is consistently inertial?
    $endgroup$
    – Roberto Singer
    3 hours ago











  • $begingroup$
    @RobertoSinger Acceleration isn't subjective
    $endgroup$
    – Aaron Stevens
    2 hours ago















1












$begingroup$


I'm a beginner physics student only studying elementary AP-level physics and calculus, so when I came across the conceptual basis of the twins paradox I was, of course curious. People often explain the paradox away by explaining how the symmetry from each perspective is broken, without satisfactorily illustrating why. Before I ask my question I want to explain from my understanding-



So you have a twin on earth who understands that his twin is on a spaceship accelerating away arbitrarily close to the speed of light then returning home. He accelerates away and comes back, and I understand why the twin on the spaceship believes the other is older- Because on a spacetime diagram, we recognize that the axis flips and the twin on the ship understands that the relativistic affect on him will result in a difference.



So my question is: How do both observers figure out WHO is accelerating to begin with? To illustrate my problem with the paradox, I instead imagine two twins floating in space 1 meter apart in a vacuum, until one sees the other accelerate to near light speed. If we assume that the twins will return to their initial position at 1 meter apart, only ONE of them will age. The problem is figuring out who?



This is because: If twin A assumes he is stationary, and twin B assumes he is accelerating, then they can work out the respective maths. But what happens if both assume that they are accelerating, or that both are stationary? This is what results in the apparent paradox isn't it? So the real question should be: How do we know who is objectively accelerating?










share|cite|improve this question









New contributor




Roberto Singer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$







  • 3




    $begingroup$
    Possible duplicate of What is the proper way to explain the twin paradox?
    $endgroup$
    – StephenG
    3 hours ago











  • $begingroup$
    No, these answers all assume from the getgo that one twin is accelerating and knows he is accelerating, and the other twin is stationary and knows he is stationary, and both observers agree on who is what. If all you know is that the other observer is accelerating, how do you measure which of the twins is really experiencing acceleration? The paradox arises when each twin assumes he is stationary/accelerating. If they agree on which is which its easy to make the calculations, but how can they objectively measure whose frame is consistently inertial?
    $endgroup$
    – Roberto Singer
    3 hours ago











  • $begingroup$
    @RobertoSinger Acceleration isn't subjective
    $endgroup$
    – Aaron Stevens
    2 hours ago













1












1








1





$begingroup$


I'm a beginner physics student only studying elementary AP-level physics and calculus, so when I came across the conceptual basis of the twins paradox I was, of course curious. People often explain the paradox away by explaining how the symmetry from each perspective is broken, without satisfactorily illustrating why. Before I ask my question I want to explain from my understanding-



So you have a twin on earth who understands that his twin is on a spaceship accelerating away arbitrarily close to the speed of light then returning home. He accelerates away and comes back, and I understand why the twin on the spaceship believes the other is older- Because on a spacetime diagram, we recognize that the axis flips and the twin on the ship understands that the relativistic affect on him will result in a difference.



So my question is: How do both observers figure out WHO is accelerating to begin with? To illustrate my problem with the paradox, I instead imagine two twins floating in space 1 meter apart in a vacuum, until one sees the other accelerate to near light speed. If we assume that the twins will return to their initial position at 1 meter apart, only ONE of them will age. The problem is figuring out who?



This is because: If twin A assumes he is stationary, and twin B assumes he is accelerating, then they can work out the respective maths. But what happens if both assume that they are accelerating, or that both are stationary? This is what results in the apparent paradox isn't it? So the real question should be: How do we know who is objectively accelerating?










share|cite|improve this question









New contributor




Roberto Singer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







$endgroup$




I'm a beginner physics student only studying elementary AP-level physics and calculus, so when I came across the conceptual basis of the twins paradox I was, of course curious. People often explain the paradox away by explaining how the symmetry from each perspective is broken, without satisfactorily illustrating why. Before I ask my question I want to explain from my understanding-



So you have a twin on earth who understands that his twin is on a spaceship accelerating away arbitrarily close to the speed of light then returning home. He accelerates away and comes back, and I understand why the twin on the spaceship believes the other is older- Because on a spacetime diagram, we recognize that the axis flips and the twin on the ship understands that the relativistic affect on him will result in a difference.



So my question is: How do both observers figure out WHO is accelerating to begin with? To illustrate my problem with the paradox, I instead imagine two twins floating in space 1 meter apart in a vacuum, until one sees the other accelerate to near light speed. If we assume that the twins will return to their initial position at 1 meter apart, only ONE of them will age. The problem is figuring out who?



This is because: If twin A assumes he is stationary, and twin B assumes he is accelerating, then they can work out the respective maths. But what happens if both assume that they are accelerating, or that both are stationary? This is what results in the apparent paradox isn't it? So the real question should be: How do we know who is objectively accelerating?







special-relativity reference-frames acceleration






share|cite|improve this question









New contributor




Roberto Singer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











share|cite|improve this question









New contributor




Roberto Singer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|cite|improve this question




share|cite|improve this question








edited 2 hours ago









Qmechanic

108k122001249




108k122001249






New contributor




Roberto Singer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









asked 3 hours ago









Roberto SingerRoberto Singer

82




82




New contributor




Roberto Singer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.





New contributor





Roberto Singer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Roberto Singer is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.







  • 3




    $begingroup$
    Possible duplicate of What is the proper way to explain the twin paradox?
    $endgroup$
    – StephenG
    3 hours ago











  • $begingroup$
    No, these answers all assume from the getgo that one twin is accelerating and knows he is accelerating, and the other twin is stationary and knows he is stationary, and both observers agree on who is what. If all you know is that the other observer is accelerating, how do you measure which of the twins is really experiencing acceleration? The paradox arises when each twin assumes he is stationary/accelerating. If they agree on which is which its easy to make the calculations, but how can they objectively measure whose frame is consistently inertial?
    $endgroup$
    – Roberto Singer
    3 hours ago











  • $begingroup$
    @RobertoSinger Acceleration isn't subjective
    $endgroup$
    – Aaron Stevens
    2 hours ago












  • 3




    $begingroup$
    Possible duplicate of What is the proper way to explain the twin paradox?
    $endgroup$
    – StephenG
    3 hours ago











  • $begingroup$
    No, these answers all assume from the getgo that one twin is accelerating and knows he is accelerating, and the other twin is stationary and knows he is stationary, and both observers agree on who is what. If all you know is that the other observer is accelerating, how do you measure which of the twins is really experiencing acceleration? The paradox arises when each twin assumes he is stationary/accelerating. If they agree on which is which its easy to make the calculations, but how can they objectively measure whose frame is consistently inertial?
    $endgroup$
    – Roberto Singer
    3 hours ago











  • $begingroup$
    @RobertoSinger Acceleration isn't subjective
    $endgroup$
    – Aaron Stevens
    2 hours ago







3




3




$begingroup$
Possible duplicate of What is the proper way to explain the twin paradox?
$endgroup$
– StephenG
3 hours ago





$begingroup$
Possible duplicate of What is the proper way to explain the twin paradox?
$endgroup$
– StephenG
3 hours ago













$begingroup$
No, these answers all assume from the getgo that one twin is accelerating and knows he is accelerating, and the other twin is stationary and knows he is stationary, and both observers agree on who is what. If all you know is that the other observer is accelerating, how do you measure which of the twins is really experiencing acceleration? The paradox arises when each twin assumes he is stationary/accelerating. If they agree on which is which its easy to make the calculations, but how can they objectively measure whose frame is consistently inertial?
$endgroup$
– Roberto Singer
3 hours ago





$begingroup$
No, these answers all assume from the getgo that one twin is accelerating and knows he is accelerating, and the other twin is stationary and knows he is stationary, and both observers agree on who is what. If all you know is that the other observer is accelerating, how do you measure which of the twins is really experiencing acceleration? The paradox arises when each twin assumes he is stationary/accelerating. If they agree on which is which its easy to make the calculations, but how can they objectively measure whose frame is consistently inertial?
$endgroup$
– Roberto Singer
3 hours ago













$begingroup$
@RobertoSinger Acceleration isn't subjective
$endgroup$
– Aaron Stevens
2 hours ago




$begingroup$
@RobertoSinger Acceleration isn't subjective
$endgroup$
– Aaron Stevens
2 hours ago










1 Answer
1






active

oldest

votes


















4












$begingroup$

The resolution to the paradox is that, although velocity is relative, acceleration is in general not, so the situation is not actually symmetric. An easy way to see this is to imagine what you feel when your car accelerates: you feel your seat push you forward, or when you slam on the brakes you feel your seatbelt hold you back. You do not feel the same effects when you look at some other car that is accelerating "relative to you."



These are measurable effects, so each twin can independently determine whether she is herself accelerating, in addition to looking at the other twin's motion. Thus there is no ambiguity in which twin accelerates.



Note: I'm posting this answer because it is simple, even though this is indeed a duplicate of What is the proper way to explain the twin paradox. See the answers there for a more detailed description of what is actually going on.






share|cite|improve this answer








New contributor




Will is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$












  • $begingroup$
    That's actually a perfect answer, exactly what I was looking for! Thanks!
    $endgroup$
    – Roberto Singer
    2 hours ago










  • $begingroup$
    Cheers, I'm so glad it was helpful! Good luck with your continued study :)
    $endgroup$
    – Will
    2 hours ago











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1 Answer
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1 Answer
1






active

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active

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active

oldest

votes









4












$begingroup$

The resolution to the paradox is that, although velocity is relative, acceleration is in general not, so the situation is not actually symmetric. An easy way to see this is to imagine what you feel when your car accelerates: you feel your seat push you forward, or when you slam on the brakes you feel your seatbelt hold you back. You do not feel the same effects when you look at some other car that is accelerating "relative to you."



These are measurable effects, so each twin can independently determine whether she is herself accelerating, in addition to looking at the other twin's motion. Thus there is no ambiguity in which twin accelerates.



Note: I'm posting this answer because it is simple, even though this is indeed a duplicate of What is the proper way to explain the twin paradox. See the answers there for a more detailed description of what is actually going on.






share|cite|improve this answer








New contributor




Will is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$












  • $begingroup$
    That's actually a perfect answer, exactly what I was looking for! Thanks!
    $endgroup$
    – Roberto Singer
    2 hours ago










  • $begingroup$
    Cheers, I'm so glad it was helpful! Good luck with your continued study :)
    $endgroup$
    – Will
    2 hours ago















4












$begingroup$

The resolution to the paradox is that, although velocity is relative, acceleration is in general not, so the situation is not actually symmetric. An easy way to see this is to imagine what you feel when your car accelerates: you feel your seat push you forward, or when you slam on the brakes you feel your seatbelt hold you back. You do not feel the same effects when you look at some other car that is accelerating "relative to you."



These are measurable effects, so each twin can independently determine whether she is herself accelerating, in addition to looking at the other twin's motion. Thus there is no ambiguity in which twin accelerates.



Note: I'm posting this answer because it is simple, even though this is indeed a duplicate of What is the proper way to explain the twin paradox. See the answers there for a more detailed description of what is actually going on.






share|cite|improve this answer








New contributor




Will is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$












  • $begingroup$
    That's actually a perfect answer, exactly what I was looking for! Thanks!
    $endgroup$
    – Roberto Singer
    2 hours ago










  • $begingroup$
    Cheers, I'm so glad it was helpful! Good luck with your continued study :)
    $endgroup$
    – Will
    2 hours ago













4












4








4





$begingroup$

The resolution to the paradox is that, although velocity is relative, acceleration is in general not, so the situation is not actually symmetric. An easy way to see this is to imagine what you feel when your car accelerates: you feel your seat push you forward, or when you slam on the brakes you feel your seatbelt hold you back. You do not feel the same effects when you look at some other car that is accelerating "relative to you."



These are measurable effects, so each twin can independently determine whether she is herself accelerating, in addition to looking at the other twin's motion. Thus there is no ambiguity in which twin accelerates.



Note: I'm posting this answer because it is simple, even though this is indeed a duplicate of What is the proper way to explain the twin paradox. See the answers there for a more detailed description of what is actually going on.






share|cite|improve this answer








New contributor




Will is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






$endgroup$



The resolution to the paradox is that, although velocity is relative, acceleration is in general not, so the situation is not actually symmetric. An easy way to see this is to imagine what you feel when your car accelerates: you feel your seat push you forward, or when you slam on the brakes you feel your seatbelt hold you back. You do not feel the same effects when you look at some other car that is accelerating "relative to you."



These are measurable effects, so each twin can independently determine whether she is herself accelerating, in addition to looking at the other twin's motion. Thus there is no ambiguity in which twin accelerates.



Note: I'm posting this answer because it is simple, even though this is indeed a duplicate of What is the proper way to explain the twin paradox. See the answers there for a more detailed description of what is actually going on.







share|cite|improve this answer








New contributor




Will is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









share|cite|improve this answer



share|cite|improve this answer






New contributor




Will is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.









answered 3 hours ago









WillWill

1114




1114




New contributor




Will is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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New contributor





Will is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.






Will is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











  • $begingroup$
    That's actually a perfect answer, exactly what I was looking for! Thanks!
    $endgroup$
    – Roberto Singer
    2 hours ago










  • $begingroup$
    Cheers, I'm so glad it was helpful! Good luck with your continued study :)
    $endgroup$
    – Will
    2 hours ago
















  • $begingroup$
    That's actually a perfect answer, exactly what I was looking for! Thanks!
    $endgroup$
    – Roberto Singer
    2 hours ago










  • $begingroup$
    Cheers, I'm so glad it was helpful! Good luck with your continued study :)
    $endgroup$
    – Will
    2 hours ago















$begingroup$
That's actually a perfect answer, exactly what I was looking for! Thanks!
$endgroup$
– Roberto Singer
2 hours ago




$begingroup$
That's actually a perfect answer, exactly what I was looking for! Thanks!
$endgroup$
– Roberto Singer
2 hours ago












$begingroup$
Cheers, I'm so glad it was helpful! Good luck with your continued study :)
$endgroup$
– Will
2 hours ago




$begingroup$
Cheers, I'm so glad it was helpful! Good luck with your continued study :)
$endgroup$
– Will
2 hours ago










Roberto Singer is a new contributor. Be nice, and check out our Code of Conduct.









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Roberto Singer is a new contributor. Be nice, and check out our Code of Conduct.












Roberto Singer is a new contributor. Be nice, and check out our Code of Conduct.











Roberto Singer is a new contributor. Be nice, and check out our Code of Conduct.














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Are there any AGPL-style licences that require source code modifications to be public? Planned maintenance scheduled April 23, 2019 at 23:30 UTC (7:30pm US/Eastern) Announcing the arrival of Valued Associate #679: Cesar Manara Unicorn Meta Zoo #1: Why another podcast?Force derivative works to be publicAre there any GPL like licenses for Apple App Store?Do you violate the GPL if you provide source code that cannot be compiled?GPL - is it distribution to use libraries in an appliance loaned to customers?Distributing App for free which uses GPL'ed codeModifications of server software under GPL, with web/CLI interfaceDoes using an AGPLv3-licensed library prevent me from dual-licensing my own source code?Can I publish only select code under GPLv3 from a private project?Is there published precedent regarding the scope of covered work that uses AGPL software?If MIT licensed code links to GPL licensed code what should be the license of the resulting binary program?If I use a public API endpoint that has its source code licensed under AGPL in my app, do I need to disclose my source?

2013 GY136 Descoberta | Órbita | Referências Menu de navegação«List Of Centaurs and Scattered-Disk Objects»«List of Known Trans-Neptunian Objects»

Mortes em março de 2019 Referências Menu de navegação«Zhores Alferov, Nobel de Física bielorrusso, morre aos 88 anos - Ciência»«Fallece Rafael Torija, o bispo emérito de Ciudad Real»«Peter Hurford dies at 88»«Keith Flint, vocalista do The Prodigy, morre aos 49 anos»«Luke Perry, ator de 'Barrados no baile' e 'Riverdale', morre aos 52 anos»«Former Rangers and Scotland captain Eric Caldow dies, aged 84»«Morreu, aos 61 anos, a antiga lenda do wrestling King Kong Bundy»«Fallece el actor y director teatral Abraham Stavans»«In Memoriam Guillaume Faye»«Sidney Sheinberg, a Force Behind Universal and Spielberg, Is Dead at 84»«Carmine Persico, Colombo Crime Family Boss, Is Dead at 85»«Dirigent Michael Gielen gestorben»«Ciclista tricampeã mundial e prata na Rio 2016 é encontrada morta em casa aos 23 anos»«Pagan Community Notes: Raven Grimassi dies, Indianapolis pop-up event cancelled, Circle Sanctuary announces new podcast, and more!»«Hal Blaine, Wrecking Crew Drummer, Dies at 90»«Morre Coutinho, que editou dupla lendária com Pelé no Santos»«Cantor Demétrius, ídolo da Jovem Guarda, morre em SP»«Ex-presidente do Vasco, Eurico Miranda morre no Rio de Janeiro»«Bronze no Mundial de basquete de 1971, Laís Elena morre aos 76 anos»«Diretor de Corridas da F1, Charlie Whiting morre aos 66 anos às vésperas do GP da Austrália»«Morreu o cardeal Danneels, da Bélgica»«Morreu o cartoonista Augusto Cid»«Morreu a atriz Maria Isabel de Lizandra, de "Vale Tudo" e novelas da Tupi»«WS Merwin, prize-winning poet of nature, dies at 91»«Atriz Márcia Real morre em São Paulo aos 88 anos»«Mauritanie: décès de l'ancien président Mohamed Mahmoud ould Louly»«Morreu Dick Dale, o rei da surf guitar e de "Pulp Fiction"»«Falleció Víctor Genes»«João Carlos Marinho, autor de 'O Gênio do Crime', morre em SP»«Legendary Horror Director and SFX Artist John Carl Buechler Dies at 66»«Morre em Salvador a religiosa Makota Valdina»«مرگ بازیکن‌ سابق نساجی بر اثر سقوط سنگ در مازندران»«Domingos Oliveira morre no Rio»«Morre Airton Ravagniani, ex-São Paulo, Fla, Vasco, Grêmio e Sport - Notícias»«Morre o escritor Flavio Moreira da Costa»«Larry Cohen, Writer-Director of 'It's Alive' and 'Hell Up in Harlem,' Dies at 77»«Scott Walker, experimental singer-songwriter, dead at 76»«Joseph Pilato, Day of the Dead Star and Horror Favorite, Dies at 70»«Sheffield United set to pay tribute to legendary goalkeeper Ted Burgin who has died at 91»«Morre Rafael Henzel, sobrevivente de acidente aéreo da Chapecoense»«Morre Valery Bykovsky, um dos primeiros cosmonautas da União Soviética»«Agnès Varda, cineasta da Nouvelle Vague, morre aos 90 anos»«Agnès Varda, cineasta francesa, morre aos 90 anos»«Tania Mallet, James Bond Actress and Helen Mirren's Cousin, Dies at 77»e