How to test the equality of two Pearson correlation coefficients computed from the same sample? The 2019 Stack Overflow Developer Survey Results Are In Announcing the arrival of Valued Associate #679: Cesar Manara Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Should I reverse score items before running reliability analyses (item-total correlation) and factor analysis?Significance test on the difference of Spearman's correlation coefficientHow can you run a correlation coefficient test among two ordinal variables with uneven scales?How can two positive dependent correlation coefficients differ significantly without differing significantly from zero?How to compare two Pearson correlation coefficientsAlternative to Pearson correlation testDifference Between Two Correlation Coefficients - questionsWhich Two-Sample Test for Non-Independent Data?Comparison of two correlationsWhat is the relationship between an average of correlations and a correlation for an average of the same variables?

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How to test the equality of two Pearson correlation coefficients computed from the same sample?



The 2019 Stack Overflow Developer Survey Results Are In
Announcing the arrival of Valued Associate #679: Cesar Manara
Planned maintenance scheduled April 17/18, 2019 at 00:00UTC (8:00pm US/Eastern)Should I reverse score items before running reliability analyses (item-total correlation) and factor analysis?Significance test on the difference of Spearman's correlation coefficientHow can you run a correlation coefficient test among two ordinal variables with uneven scales?How can two positive dependent correlation coefficients differ significantly without differing significantly from zero?How to compare two Pearson correlation coefficientsAlternative to Pearson correlation testDifference Between Two Correlation Coefficients - questionsWhich Two-Sample Test for Non-Independent Data?Comparison of two correlationsWhat is the relationship between an average of correlations and a correlation for an average of the same variables?



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$begingroup$


Is there a reliable way to say if two Pearson correlations from the same sample (do not) differ significantly? More concrete, I calculated the correlation between a total score on a questionnaire and an other variable, and a subscore of the same questionnaire and the variable. The correlations are respectively .239 and .234, so they look quite similar to me. (The other two subscales did not significantly correlate with the variable). Could I use a fisher Z to check if the two correlations indeed do not significantly differ, or is the fact that they are not independent a problem?










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    3












    $begingroup$


    Is there a reliable way to say if two Pearson correlations from the same sample (do not) differ significantly? More concrete, I calculated the correlation between a total score on a questionnaire and an other variable, and a subscore of the same questionnaire and the variable. The correlations are respectively .239 and .234, so they look quite similar to me. (The other two subscales did not significantly correlate with the variable). Could I use a fisher Z to check if the two correlations indeed do not significantly differ, or is the fact that they are not independent a problem?










    share|cite|improve this question









    New contributor




    ChaFo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.







    $endgroup$














      3












      3








      3


      2



      $begingroup$


      Is there a reliable way to say if two Pearson correlations from the same sample (do not) differ significantly? More concrete, I calculated the correlation between a total score on a questionnaire and an other variable, and a subscore of the same questionnaire and the variable. The correlations are respectively .239 and .234, so they look quite similar to me. (The other two subscales did not significantly correlate with the variable). Could I use a fisher Z to check if the two correlations indeed do not significantly differ, or is the fact that they are not independent a problem?










      share|cite|improve this question









      New contributor




      ChaFo is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.







      $endgroup$




      Is there a reliable way to say if two Pearson correlations from the same sample (do not) differ significantly? More concrete, I calculated the correlation between a total score on a questionnaire and an other variable, and a subscore of the same questionnaire and the variable. The correlations are respectively .239 and .234, so they look quite similar to me. (The other two subscales did not significantly correlate with the variable). Could I use a fisher Z to check if the two correlations indeed do not significantly differ, or is the fact that they are not independent a problem?







      hypothesis-testing correlation non-independent






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      edited 22 mins ago









      amoeba

      62.3k15208267




      62.3k15208267






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      asked 12 hours ago









      ChaFoChaFo

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      161




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          3 Answers
          3






          active

          oldest

          votes


















          4












          $begingroup$

          Firstly I would point out that these correlations are fairly low.



          Second, have you plotted the data to investigate possible non-linear associations?



          Third, I would say that common sense should dictate that correlations of 0.239 and 0.234 are essentially the same and searching for a test to confirm this, unless the sample size is absolutely enormous, is folly.



          Fourth, you could calculate confidence intervals for both statistics, and if they do not overlap, then you can conclude that they are statistically significantly different. However, this would be invalid since the 2 samples are not independent. Moreover, as per my third point, even if you did have such an enormous sample and a test which validly concluded that a significant difference exists, I would find it hard to belive that the difference was practically significant.






          share|cite|improve this answer









          $endgroup$




















            4












            $begingroup$

            Expanding on Robert Long's answer (+1 to Robert) I'd say that testing for a difference between these is folly, regardless of sample size. Look! Is 0.239 different from 0.234? Well, maybe it is. There are situations where a very small effect size is very important. If a plane crashes 1 in 1,000 flights, that's a big big problem. I can't think, offhand, of a situation where this tiny difference in correlations could be meaningful, but maybe there is one. Whether it is significant or not is not the point.



            Also, the dependence will surely be a problem. If you really wanted to see something like this, I'd find a third correlation: The correlation between the test after removing the subtest. Then you can compare that to the correlation with the subtest.



            Finally, it's unclear to me what you are trying to show, but I think you are trying to show that these are not different. In that case, the usual null hypothesis tests are inappropriate. You should be looking at tests of equivalence (if, in fact you want to look at significance at all).






            share|cite|improve this answer









            $endgroup$








            • 1




              $begingroup$
              Excellent points, Peter (+1)
              $endgroup$
              – Robert Long
              8 hours ago






            • 1




              $begingroup$
              Peter Flom, the population perspective in epidemiology says, in effect, that a tiny change in risk—one that is so small as to be effectively inconsequential clinically—is a big deal if it is multiplied across an entire population. Changing someone's risk of stroke by 1 in 10,000 per year is kinda meh. Changing 10,000,000 people's risk of stroke by 1 in 10,000 is a change of a 1,000 strokes per year: a big deal. See Rose, G. (1985). Sick individuals and sick populations. International Journal of Epidemiology, 14(1), 32–28.
              $endgroup$
              – Alexis
              3 hours ago










            • $begingroup$
              Of course, Pearson's correlation coefficient alone isn't likely to be the most used measure of contrasts in risk, but I think small associations can matter.
              $endgroup$
              – Alexis
              3 hours ago


















            0












            $begingroup$

            Yes, it is possible to perform a significance test using the Fisher transform. This also depends on $N$, the number of samples used to compute the Pearson correlations. This blog post describes the method in more detail, and provides R code for it.






            share|cite|improve this answer








            New contributor




            Bai is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
            Check out our Code of Conduct.






            $endgroup$








            • 2




              $begingroup$
              Your reference is inappropriate for comparing correlation coefficients that share data, as is the case here. The OP points out that "the fact they are not independent" is the problem.
              $endgroup$
              – whuber
              5 hours ago






            • 1




              $begingroup$
              Yes, I see. OP's situation involves overlap between the two datasets, but is not a case of paired data. Therefore, my answer is inappropriate.
              $endgroup$
              – Bai
              5 hours ago










            • $begingroup$
              Actually, it sounds like the data are triples: that's what makes it possible to compute more than one correlation coefficient.
              $endgroup$
              – whuber
              4 hours ago











            Your Answer








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            3 Answers
            3






            active

            oldest

            votes








            3 Answers
            3






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            4












            $begingroup$

            Firstly I would point out that these correlations are fairly low.



            Second, have you plotted the data to investigate possible non-linear associations?



            Third, I would say that common sense should dictate that correlations of 0.239 and 0.234 are essentially the same and searching for a test to confirm this, unless the sample size is absolutely enormous, is folly.



            Fourth, you could calculate confidence intervals for both statistics, and if they do not overlap, then you can conclude that they are statistically significantly different. However, this would be invalid since the 2 samples are not independent. Moreover, as per my third point, even if you did have such an enormous sample and a test which validly concluded that a significant difference exists, I would find it hard to belive that the difference was practically significant.






            share|cite|improve this answer









            $endgroup$

















              4












              $begingroup$

              Firstly I would point out that these correlations are fairly low.



              Second, have you plotted the data to investigate possible non-linear associations?



              Third, I would say that common sense should dictate that correlations of 0.239 and 0.234 are essentially the same and searching for a test to confirm this, unless the sample size is absolutely enormous, is folly.



              Fourth, you could calculate confidence intervals for both statistics, and if they do not overlap, then you can conclude that they are statistically significantly different. However, this would be invalid since the 2 samples are not independent. Moreover, as per my third point, even if you did have such an enormous sample and a test which validly concluded that a significant difference exists, I would find it hard to belive that the difference was practically significant.






              share|cite|improve this answer









              $endgroup$















                4












                4








                4





                $begingroup$

                Firstly I would point out that these correlations are fairly low.



                Second, have you plotted the data to investigate possible non-linear associations?



                Third, I would say that common sense should dictate that correlations of 0.239 and 0.234 are essentially the same and searching for a test to confirm this, unless the sample size is absolutely enormous, is folly.



                Fourth, you could calculate confidence intervals for both statistics, and if they do not overlap, then you can conclude that they are statistically significantly different. However, this would be invalid since the 2 samples are not independent. Moreover, as per my third point, even if you did have such an enormous sample and a test which validly concluded that a significant difference exists, I would find it hard to belive that the difference was practically significant.






                share|cite|improve this answer









                $endgroup$



                Firstly I would point out that these correlations are fairly low.



                Second, have you plotted the data to investigate possible non-linear associations?



                Third, I would say that common sense should dictate that correlations of 0.239 and 0.234 are essentially the same and searching for a test to confirm this, unless the sample size is absolutely enormous, is folly.



                Fourth, you could calculate confidence intervals for both statistics, and if they do not overlap, then you can conclude that they are statistically significantly different. However, this would be invalid since the 2 samples are not independent. Moreover, as per my third point, even if you did have such an enormous sample and a test which validly concluded that a significant difference exists, I would find it hard to belive that the difference was practically significant.







                share|cite|improve this answer












                share|cite|improve this answer



                share|cite|improve this answer










                answered 10 hours ago









                Robert LongRobert Long

                11.9k22552




                11.9k22552























                    4












                    $begingroup$

                    Expanding on Robert Long's answer (+1 to Robert) I'd say that testing for a difference between these is folly, regardless of sample size. Look! Is 0.239 different from 0.234? Well, maybe it is. There are situations where a very small effect size is very important. If a plane crashes 1 in 1,000 flights, that's a big big problem. I can't think, offhand, of a situation where this tiny difference in correlations could be meaningful, but maybe there is one. Whether it is significant or not is not the point.



                    Also, the dependence will surely be a problem. If you really wanted to see something like this, I'd find a third correlation: The correlation between the test after removing the subtest. Then you can compare that to the correlation with the subtest.



                    Finally, it's unclear to me what you are trying to show, but I think you are trying to show that these are not different. In that case, the usual null hypothesis tests are inappropriate. You should be looking at tests of equivalence (if, in fact you want to look at significance at all).






                    share|cite|improve this answer









                    $endgroup$








                    • 1




                      $begingroup$
                      Excellent points, Peter (+1)
                      $endgroup$
                      – Robert Long
                      8 hours ago






                    • 1




                      $begingroup$
                      Peter Flom, the population perspective in epidemiology says, in effect, that a tiny change in risk—one that is so small as to be effectively inconsequential clinically—is a big deal if it is multiplied across an entire population. Changing someone's risk of stroke by 1 in 10,000 per year is kinda meh. Changing 10,000,000 people's risk of stroke by 1 in 10,000 is a change of a 1,000 strokes per year: a big deal. See Rose, G. (1985). Sick individuals and sick populations. International Journal of Epidemiology, 14(1), 32–28.
                      $endgroup$
                      – Alexis
                      3 hours ago










                    • $begingroup$
                      Of course, Pearson's correlation coefficient alone isn't likely to be the most used measure of contrasts in risk, but I think small associations can matter.
                      $endgroup$
                      – Alexis
                      3 hours ago















                    4












                    $begingroup$

                    Expanding on Robert Long's answer (+1 to Robert) I'd say that testing for a difference between these is folly, regardless of sample size. Look! Is 0.239 different from 0.234? Well, maybe it is. There are situations where a very small effect size is very important. If a plane crashes 1 in 1,000 flights, that's a big big problem. I can't think, offhand, of a situation where this tiny difference in correlations could be meaningful, but maybe there is one. Whether it is significant or not is not the point.



                    Also, the dependence will surely be a problem. If you really wanted to see something like this, I'd find a third correlation: The correlation between the test after removing the subtest. Then you can compare that to the correlation with the subtest.



                    Finally, it's unclear to me what you are trying to show, but I think you are trying to show that these are not different. In that case, the usual null hypothesis tests are inappropriate. You should be looking at tests of equivalence (if, in fact you want to look at significance at all).






                    share|cite|improve this answer









                    $endgroup$








                    • 1




                      $begingroup$
                      Excellent points, Peter (+1)
                      $endgroup$
                      – Robert Long
                      8 hours ago






                    • 1




                      $begingroup$
                      Peter Flom, the population perspective in epidemiology says, in effect, that a tiny change in risk—one that is so small as to be effectively inconsequential clinically—is a big deal if it is multiplied across an entire population. Changing someone's risk of stroke by 1 in 10,000 per year is kinda meh. Changing 10,000,000 people's risk of stroke by 1 in 10,000 is a change of a 1,000 strokes per year: a big deal. See Rose, G. (1985). Sick individuals and sick populations. International Journal of Epidemiology, 14(1), 32–28.
                      $endgroup$
                      – Alexis
                      3 hours ago










                    • $begingroup$
                      Of course, Pearson's correlation coefficient alone isn't likely to be the most used measure of contrasts in risk, but I think small associations can matter.
                      $endgroup$
                      – Alexis
                      3 hours ago













                    4












                    4








                    4





                    $begingroup$

                    Expanding on Robert Long's answer (+1 to Robert) I'd say that testing for a difference between these is folly, regardless of sample size. Look! Is 0.239 different from 0.234? Well, maybe it is. There are situations where a very small effect size is very important. If a plane crashes 1 in 1,000 flights, that's a big big problem. I can't think, offhand, of a situation where this tiny difference in correlations could be meaningful, but maybe there is one. Whether it is significant or not is not the point.



                    Also, the dependence will surely be a problem. If you really wanted to see something like this, I'd find a third correlation: The correlation between the test after removing the subtest. Then you can compare that to the correlation with the subtest.



                    Finally, it's unclear to me what you are trying to show, but I think you are trying to show that these are not different. In that case, the usual null hypothesis tests are inappropriate. You should be looking at tests of equivalence (if, in fact you want to look at significance at all).






                    share|cite|improve this answer









                    $endgroup$



                    Expanding on Robert Long's answer (+1 to Robert) I'd say that testing for a difference between these is folly, regardless of sample size. Look! Is 0.239 different from 0.234? Well, maybe it is. There are situations where a very small effect size is very important. If a plane crashes 1 in 1,000 flights, that's a big big problem. I can't think, offhand, of a situation where this tiny difference in correlations could be meaningful, but maybe there is one. Whether it is significant or not is not the point.



                    Also, the dependence will surely be a problem. If you really wanted to see something like this, I'd find a third correlation: The correlation between the test after removing the subtest. Then you can compare that to the correlation with the subtest.



                    Finally, it's unclear to me what you are trying to show, but I think you are trying to show that these are not different. In that case, the usual null hypothesis tests are inappropriate. You should be looking at tests of equivalence (if, in fact you want to look at significance at all).







                    share|cite|improve this answer












                    share|cite|improve this answer



                    share|cite|improve this answer










                    answered 9 hours ago









                    Peter FlomPeter Flom

                    77.4k12109217




                    77.4k12109217







                    • 1




                      $begingroup$
                      Excellent points, Peter (+1)
                      $endgroup$
                      – Robert Long
                      8 hours ago






                    • 1




                      $begingroup$
                      Peter Flom, the population perspective in epidemiology says, in effect, that a tiny change in risk—one that is so small as to be effectively inconsequential clinically—is a big deal if it is multiplied across an entire population. Changing someone's risk of stroke by 1 in 10,000 per year is kinda meh. Changing 10,000,000 people's risk of stroke by 1 in 10,000 is a change of a 1,000 strokes per year: a big deal. See Rose, G. (1985). Sick individuals and sick populations. International Journal of Epidemiology, 14(1), 32–28.
                      $endgroup$
                      – Alexis
                      3 hours ago










                    • $begingroup$
                      Of course, Pearson's correlation coefficient alone isn't likely to be the most used measure of contrasts in risk, but I think small associations can matter.
                      $endgroup$
                      – Alexis
                      3 hours ago












                    • 1




                      $begingroup$
                      Excellent points, Peter (+1)
                      $endgroup$
                      – Robert Long
                      8 hours ago






                    • 1




                      $begingroup$
                      Peter Flom, the population perspective in epidemiology says, in effect, that a tiny change in risk—one that is so small as to be effectively inconsequential clinically—is a big deal if it is multiplied across an entire population. Changing someone's risk of stroke by 1 in 10,000 per year is kinda meh. Changing 10,000,000 people's risk of stroke by 1 in 10,000 is a change of a 1,000 strokes per year: a big deal. See Rose, G. (1985). Sick individuals and sick populations. International Journal of Epidemiology, 14(1), 32–28.
                      $endgroup$
                      – Alexis
                      3 hours ago










                    • $begingroup$
                      Of course, Pearson's correlation coefficient alone isn't likely to be the most used measure of contrasts in risk, but I think small associations can matter.
                      $endgroup$
                      – Alexis
                      3 hours ago







                    1




                    1




                    $begingroup$
                    Excellent points, Peter (+1)
                    $endgroup$
                    – Robert Long
                    8 hours ago




                    $begingroup$
                    Excellent points, Peter (+1)
                    $endgroup$
                    – Robert Long
                    8 hours ago




                    1




                    1




                    $begingroup$
                    Peter Flom, the population perspective in epidemiology says, in effect, that a tiny change in risk—one that is so small as to be effectively inconsequential clinically—is a big deal if it is multiplied across an entire population. Changing someone's risk of stroke by 1 in 10,000 per year is kinda meh. Changing 10,000,000 people's risk of stroke by 1 in 10,000 is a change of a 1,000 strokes per year: a big deal. See Rose, G. (1985). Sick individuals and sick populations. International Journal of Epidemiology, 14(1), 32–28.
                    $endgroup$
                    – Alexis
                    3 hours ago




                    $begingroup$
                    Peter Flom, the population perspective in epidemiology says, in effect, that a tiny change in risk—one that is so small as to be effectively inconsequential clinically—is a big deal if it is multiplied across an entire population. Changing someone's risk of stroke by 1 in 10,000 per year is kinda meh. Changing 10,000,000 people's risk of stroke by 1 in 10,000 is a change of a 1,000 strokes per year: a big deal. See Rose, G. (1985). Sick individuals and sick populations. International Journal of Epidemiology, 14(1), 32–28.
                    $endgroup$
                    – Alexis
                    3 hours ago












                    $begingroup$
                    Of course, Pearson's correlation coefficient alone isn't likely to be the most used measure of contrasts in risk, but I think small associations can matter.
                    $endgroup$
                    – Alexis
                    3 hours ago




                    $begingroup$
                    Of course, Pearson's correlation coefficient alone isn't likely to be the most used measure of contrasts in risk, but I think small associations can matter.
                    $endgroup$
                    – Alexis
                    3 hours ago











                    0












                    $begingroup$

                    Yes, it is possible to perform a significance test using the Fisher transform. This also depends on $N$, the number of samples used to compute the Pearson correlations. This blog post describes the method in more detail, and provides R code for it.






                    share|cite|improve this answer








                    New contributor




                    Bai is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                    Check out our Code of Conduct.






                    $endgroup$








                    • 2




                      $begingroup$
                      Your reference is inappropriate for comparing correlation coefficients that share data, as is the case here. The OP points out that "the fact they are not independent" is the problem.
                      $endgroup$
                      – whuber
                      5 hours ago






                    • 1




                      $begingroup$
                      Yes, I see. OP's situation involves overlap between the two datasets, but is not a case of paired data. Therefore, my answer is inappropriate.
                      $endgroup$
                      – Bai
                      5 hours ago










                    • $begingroup$
                      Actually, it sounds like the data are triples: that's what makes it possible to compute more than one correlation coefficient.
                      $endgroup$
                      – whuber
                      4 hours ago















                    0












                    $begingroup$

                    Yes, it is possible to perform a significance test using the Fisher transform. This also depends on $N$, the number of samples used to compute the Pearson correlations. This blog post describes the method in more detail, and provides R code for it.






                    share|cite|improve this answer








                    New contributor




                    Bai is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                    Check out our Code of Conduct.






                    $endgroup$








                    • 2




                      $begingroup$
                      Your reference is inappropriate for comparing correlation coefficients that share data, as is the case here. The OP points out that "the fact they are not independent" is the problem.
                      $endgroup$
                      – whuber
                      5 hours ago






                    • 1




                      $begingroup$
                      Yes, I see. OP's situation involves overlap between the two datasets, but is not a case of paired data. Therefore, my answer is inappropriate.
                      $endgroup$
                      – Bai
                      5 hours ago










                    • $begingroup$
                      Actually, it sounds like the data are triples: that's what makes it possible to compute more than one correlation coefficient.
                      $endgroup$
                      – whuber
                      4 hours ago













                    0












                    0








                    0





                    $begingroup$

                    Yes, it is possible to perform a significance test using the Fisher transform. This also depends on $N$, the number of samples used to compute the Pearson correlations. This blog post describes the method in more detail, and provides R code for it.






                    share|cite|improve this answer








                    New contributor




                    Bai is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                    Check out our Code of Conduct.






                    $endgroup$



                    Yes, it is possible to perform a significance test using the Fisher transform. This also depends on $N$, the number of samples used to compute the Pearson correlations. This blog post describes the method in more detail, and provides R code for it.







                    share|cite|improve this answer








                    New contributor




                    Bai is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                    Check out our Code of Conduct.









                    share|cite|improve this answer



                    share|cite|improve this answer






                    New contributor




                    Bai is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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                    answered 5 hours ago









                    BaiBai

                    101




                    101




                    New contributor




                    Bai is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
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                    New contributor





                    Bai is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                    Check out our Code of Conduct.






                    Bai is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
                    Check out our Code of Conduct.







                    • 2




                      $begingroup$
                      Your reference is inappropriate for comparing correlation coefficients that share data, as is the case here. The OP points out that "the fact they are not independent" is the problem.
                      $endgroup$
                      – whuber
                      5 hours ago






                    • 1




                      $begingroup$
                      Yes, I see. OP's situation involves overlap between the two datasets, but is not a case of paired data. Therefore, my answer is inappropriate.
                      $endgroup$
                      – Bai
                      5 hours ago










                    • $begingroup$
                      Actually, it sounds like the data are triples: that's what makes it possible to compute more than one correlation coefficient.
                      $endgroup$
                      – whuber
                      4 hours ago












                    • 2




                      $begingroup$
                      Your reference is inappropriate for comparing correlation coefficients that share data, as is the case here. The OP points out that "the fact they are not independent" is the problem.
                      $endgroup$
                      – whuber
                      5 hours ago






                    • 1




                      $begingroup$
                      Yes, I see. OP's situation involves overlap between the two datasets, but is not a case of paired data. Therefore, my answer is inappropriate.
                      $endgroup$
                      – Bai
                      5 hours ago










                    • $begingroup$
                      Actually, it sounds like the data are triples: that's what makes it possible to compute more than one correlation coefficient.
                      $endgroup$
                      – whuber
                      4 hours ago







                    2




                    2




                    $begingroup$
                    Your reference is inappropriate for comparing correlation coefficients that share data, as is the case here. The OP points out that "the fact they are not independent" is the problem.
                    $endgroup$
                    – whuber
                    5 hours ago




                    $begingroup$
                    Your reference is inappropriate for comparing correlation coefficients that share data, as is the case here. The OP points out that "the fact they are not independent" is the problem.
                    $endgroup$
                    – whuber
                    5 hours ago




                    1




                    1




                    $begingroup$
                    Yes, I see. OP's situation involves overlap between the two datasets, but is not a case of paired data. Therefore, my answer is inappropriate.
                    $endgroup$
                    – Bai
                    5 hours ago




                    $begingroup$
                    Yes, I see. OP's situation involves overlap between the two datasets, but is not a case of paired data. Therefore, my answer is inappropriate.
                    $endgroup$
                    – Bai
                    5 hours ago












                    $begingroup$
                    Actually, it sounds like the data are triples: that's what makes it possible to compute more than one correlation coefficient.
                    $endgroup$
                    – whuber
                    4 hours ago




                    $begingroup$
                    Actually, it sounds like the data are triples: that's what makes it possible to compute more than one correlation coefficient.
                    $endgroup$
                    – whuber
                    4 hours ago










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