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What expression will give age in years in QGIS?
The Next CEO of Stack OverflowQGIS Points to Path Plugin Date/time errorHow can I get the field index of the new layer in my script using Python?plugin manager fault installationSeparate a string value in two integers in QGISHow to call default tool in QGIS inside plugin using python script?clustering categorized datawriting an expression in qgis (2.14.0)What has replaced QGIS SPIT (Shapefile to PostGIS Import Tool)?QGIS plugin fields will not resetSending data between QGIS and other programs in real time
I have the date at which a pipe was laid. I want to create a field giving the age of the pipe in years. How do I do this in QGIS?
qgis-plugins
edited 5 hours ago
Vince
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asked 6 hours ago
TraineeGISTraineeGIS
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I have the date at which a pipe was laid. I want to create a field giving the age of the pipe in years. How do I do this in QGIS?
qgis-plugins
edited 5 hours ago
Vince
14.8k32849
asked 6 hours ago
TraineeGISTraineeGIS
113
New contributor
TraineeGIS is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
I have the date at which a pipe was laid. I want to create a field giving the age of the pipe in years. How do I do this in QGIS?
qgis-plugins
edited 5 hours ago
Vince
14.8k32849
asked 6 hours ago
TraineeGISTraineeGIS
113
New contributor
TraineeGIS is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
I have the date at which a pipe was laid. I want to create a field giving the age of the pipe in years. How do I do this in QGIS?
qgis-plugins
qgis-plugins
edited 5 hours ago
Vince
14.8k32849
asked 6 hours ago
TraineeGISTraineeGIS
113
New contributor
TraineeGIS is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 5 hours ago
Vince
14.8k32849
asked 6 hours ago
TraineeGISTraineeGIS
113
New contributor
TraineeGIS is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 5 hours ago
Vince
14.8k32849
edited 5 hours ago
Vince
14.8k32849
edited 5 hours ago
Vince
14.8k32849
14.8k32849
asked 6 hours ago
TraineeGISTraineeGIS
113
New contributor
TraineeGIS is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 6 hours ago
TraineeGISTraineeGIS
113
asked 6 hours ago
TraineeGISTraineeGIS
113
113
New contributor
TraineeGIS is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
TraineeGIS is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
TraineeGIS is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
2 Answers
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votes
Or use the age function
year(age(now() ,"yourdatefield"))
answered 5 hours ago
cskcsk
9,4601035
Sometimes I get comfortable using some function and just forget that there might be another one that saves some time... :P
– Gabriel C.
5 hours ago
add a comment |
From the field calculator, this expression could do the trick:
year(now()) - year('the laying date')
Check if the date format will work, but aside from that, it should be pretty easy. The laying date can be replaced by a field value.
answered 5 hours ago
Gabriel C.Gabriel C.
1,344320
add a comment |
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2 Answers
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active
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2 Answers
2
active
oldest
votes
active
oldest
votes
active
oldest
votes
Or use the age function
year(age(now() ,"yourdatefield"))
answered 5 hours ago
cskcsk
9,4601035
Sometimes I get comfortable using some function and just forget that there might be another one that saves some time... :P
– Gabriel C.
5 hours ago
add a comment |
Or use the age function
year(age(now() ,"yourdatefield"))
answered 5 hours ago
cskcsk
9,4601035
Sometimes I get comfortable using some function and just forget that there might be another one that saves some time... :P
– Gabriel C.
5 hours ago
add a comment |
Or use the age function
year(age(now() ,"yourdatefield"))
answered 5 hours ago
cskcsk
9,4601035
Or use the age function
year(age(now() ,"yourdatefield"))
answered 5 hours ago
cskcsk
9,4601035
answered 5 hours ago
cskcsk
9,4601035
answered 5 hours ago
cskcsk
9,4601035
answered 5 hours ago
cskcsk
9,4601035
9,4601035
Sometimes I get comfortable using some function and just forget that there might be another one that saves some time... :P
– Gabriel C.
5 hours ago
add a comment |
Sometimes I get comfortable using some function and just forget that there might be another one that saves some time... :P
– Gabriel C.
5 hours ago
Sometimes I get comfortable using some function and just forget that there might be another one that saves some time... :P
– Gabriel C.
5 hours ago
Sometimes I get comfortable using some function and just forget that there might be another one that saves some time... :P
– Gabriel C.
5 hours ago
add a comment |
From the field calculator, this expression could do the trick:
year(now()) - year('the laying date')
Check if the date format will work, but aside from that, it should be pretty easy. The laying date can be replaced by a field value.
answered 5 hours ago
Gabriel C.Gabriel C.
1,344320
add a comment |
From the field calculator, this expression could do the trick:
year(now()) - year('the laying date')
Check if the date format will work, but aside from that, it should be pretty easy. The laying date can be replaced by a field value.
answered 5 hours ago
Gabriel C.Gabriel C.
1,344320
add a comment |
From the field calculator, this expression could do the trick:
year(now()) - year('the laying date')
Check if the date format will work, but aside from that, it should be pretty easy. The laying date can be replaced by a field value.
answered 5 hours ago
Gabriel C.Gabriel C.
1,344320
From the field calculator, this expression could do the trick:
year(now()) - year('the laying date')
Check if the date format will work, but aside from that, it should be pretty easy. The laying date can be replaced by a field value.
answered 5 hours ago
Gabriel C.Gabriel C.
1,344320
answered 5 hours ago
Gabriel C.Gabriel C.
1,344320
answered 5 hours ago
Gabriel C.Gabriel C.
1,344320
answered 5 hours ago
Gabriel C.Gabriel C.
1,344320
1,344320
add a comment |
add a comment |
TraineeGIS is a new contributor. Be nice, and check out our Code of Conduct.
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