BitNot does not flip bits in the way I expectedBitwise operators - Hamlet for MathematicaHow does Mathematica decide that Log[2,8] is integer?How is the mysterious Raw function used?Graph from binary matrix (not adjacency) respecting the original matrix positionsHow to replace the selected value in matrix with a specific digit?Performance-driven approach to using Big Data without killing the hard-driveUsing the binary search algorithm in a sorted grid
How are such low op-amp input currents possible?
Why does Captain Marvel assume the planet where she lands would recognize her credentials?
Why does Deadpool say "You're welcome, Canada," after shooting Ryan Reynolds in the end credits?
Accountant/ lawyer will not return my call
Good allowance savings plan?
How does airport security verify that you can carry a battery bank over 100 Wh?
Latest web browser compatible with Windows 98
Grey hair or white hair
Is Gradient Descent central to every optimizer?
Algorithm to convert a fixed-length string to the smallest possible collision-free representation?
Can you reject a postdoc offer after the PI has paid a large sum for flights/accommodation for your visit?
Aliens englobed the Solar System: will we notice?
Could you please stop shuffling the deck and play already?
Peter's Strange Word
Does "variables should live in the smallest scope as possible" include the case "variables should not exist if possible"?
Do f-stop and exposure time perfectly cancel?
Does a Catoblepas statblock appear in an official D&D 5e product?
A three room house but a three headED dog
Why would one plane in this picture not have gear down yet?
Why doesn't this Google Translate ad use the word "Translation" instead of "Translate"?
A question on the ultrafilter number
What are the best books to study Neural Networks from a purely mathematical perspective?
How to pass a string to a command that expects a file?
Good for you! in Russian
BitNot does not flip bits in the way I expected
Bitwise operators - Hamlet for MathematicaHow does Mathematica decide that Log[2,8] is integer?How is the mysterious Raw function used?Graph from binary matrix (not adjacency) respecting the original matrix positionsHow to replace the selected value in matrix with a specific digit?Performance-driven approach to using Big Data without killing the hard-driveUsing the binary search algorithm in a sorted grid
3
$begingroup$
Can anyone explain why the last result in these statements is not the bit-flipped version of arr?
(Debug) In[189]:= arr = 0, 0, 1, 0, 0, 0, 1, 0
(Debug) Out[189]= 0, 0, 1, 0, 0, 0, 1, 0
(Debug) In[190]:= FromDigits[%, 2]
(Debug) Out[190]= 34
(Debug) In[191]:= BitNot[%]
(Debug) Out[191]= -35
(Debug) In[192]:= IntegerDigits[%, 2, 8]
(Debug) Out[192]= 0, 0, 1, 0, 0, 0, 1, 1
binary
edited 6 hours ago
m_goldberg
87.4k872198
asked 7 hours ago
bc888bc888
363
New contributor
bc888 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
|
show 4 more comments
3
$begingroup$
Can anyone explain why the last result in these statements is not the bit-flipped version of arr?
(Debug) In[189]:= arr = 0, 0, 1, 0, 0, 0, 1, 0
(Debug) Out[189]= 0, 0, 1, 0, 0, 0, 1, 0
(Debug) In[190]:= FromDigits[%, 2]
(Debug) Out[190]= 34
(Debug) In[191]:= BitNot[%]
(Debug) Out[191]= -35
(Debug) In[192]:= IntegerDigits[%, 2, 8]
(Debug) Out[192]= 0, 0, 1, 0, 0, 0, 1, 1
binary
edited 6 hours ago
m_goldberg
87.4k872198
asked 7 hours ago
bc888bc888
363
New contributor
bc888 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
4
$begingroup$
"IntegerDigits[n] discards the sign of n."
$endgroup$
– kglr
7 hours ago
$begingroup$
Is there a work around?
$endgroup$
– bc888
7 hours ago
$begingroup$
not any I know of.
$endgroup$
– kglr
7 hours ago
$begingroup$
BitNot should yield 221
$endgroup$
– bc888
7 hours ago
6
$begingroup$
Integers can have arbitrary length, so how many leading zeros should be flipped? The documentation clarifies: "Integers are assumed to be represented in two's complement form, with an unlimited number of digits, so thatBitNot[n]is simply equivalent to-1-n."
$endgroup$
– Chip Hurst
7 hours ago
|
show 4 more comments
3
3
3
1
$begingroup$
Can anyone explain why the last result in these statements is not the bit-flipped version of arr?
(Debug) In[189]:= arr = 0, 0, 1, 0, 0, 0, 1, 0
(Debug) Out[189]= 0, 0, 1, 0, 0, 0, 1, 0
(Debug) In[190]:= FromDigits[%, 2]
(Debug) Out[190]= 34
(Debug) In[191]:= BitNot[%]
(Debug) Out[191]= -35
(Debug) In[192]:= IntegerDigits[%, 2, 8]
(Debug) Out[192]= 0, 0, 1, 0, 0, 0, 1, 1
binary
edited 6 hours ago
m_goldberg
87.4k872198
asked 7 hours ago
bc888bc888
363
New contributor
bc888 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
Can anyone explain why the last result in these statements is not the bit-flipped version of arr?
(Debug) In[189]:= arr = 0, 0, 1, 0, 0, 0, 1, 0
(Debug) Out[189]= 0, 0, 1, 0, 0, 0, 1, 0
(Debug) In[190]:= FromDigits[%, 2]
(Debug) Out[190]= 34
(Debug) In[191]:= BitNot[%]
(Debug) Out[191]= -35
(Debug) In[192]:= IntegerDigits[%, 2, 8]
(Debug) Out[192]= 0, 0, 1, 0, 0, 0, 1, 1
binary
binary
edited 6 hours ago
m_goldberg
87.4k872198
asked 7 hours ago
bc888bc888
363
New contributor
bc888 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 6 hours ago
m_goldberg
87.4k872198
asked 7 hours ago
bc888bc888
363
New contributor
bc888 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
edited 6 hours ago
m_goldberg
87.4k872198
edited 6 hours ago
m_goldberg
87.4k872198
edited 6 hours ago
m_goldberg
87.4k872198
87.4k872198
asked 7 hours ago
bc888bc888
363
New contributor
bc888 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
asked 7 hours ago
bc888bc888
363
asked 7 hours ago
bc888bc888
363
363
New contributor
bc888 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
bc888 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
bc888 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
4
$begingroup$
"IntegerDigits[n] discards the sign of n."
$endgroup$
– kglr
7 hours ago
$begingroup$
Is there a work around?
$endgroup$
– bc888
7 hours ago
$begingroup$
not any I know of.
$endgroup$
– kglr
7 hours ago
$begingroup$
BitNot should yield 221
$endgroup$
– bc888
7 hours ago
6
$begingroup$
Integers can have arbitrary length, so how many leading zeros should be flipped? The documentation clarifies: "Integers are assumed to be represented in two's complement form, with an unlimited number of digits, so thatBitNot[n]is simply equivalent to-1-n."
$endgroup$
– Chip Hurst
7 hours ago
|
show 4 more comments
4
$begingroup$
"IntegerDigits[n] discards the sign of n."
$endgroup$
– kglr
7 hours ago
$begingroup$
Is there a work around?
$endgroup$
– bc888
7 hours ago
$begingroup$
not any I know of.
$endgroup$
– kglr
7 hours ago
$begingroup$
BitNot should yield 221
$endgroup$
– bc888
7 hours ago
6
$begingroup$
Integers can have arbitrary length, so how many leading zeros should be flipped? The documentation clarifies: "Integers are assumed to be represented in two's complement form, with an unlimited number of digits, so thatBitNot[n]is simply equivalent to-1-n."
$endgroup$
– Chip Hurst
7 hours ago
4
4
$begingroup$
"IntegerDigits[n] discards the sign of n."
$endgroup$
– kglr
7 hours ago
$begingroup$
"IntegerDigits[n] discards the sign of n."
$endgroup$
– kglr
7 hours ago
$begingroup$
Is there a work around?
$endgroup$
– bc888
7 hours ago
$begingroup$
Is there a work around?
$endgroup$
– bc888
7 hours ago
$begingroup$
not any I know of.
$endgroup$
– kglr
7 hours ago
$begingroup$
not any I know of.
$endgroup$
– kglr
7 hours ago
$begingroup$
BitNot should yield 221
$endgroup$
– bc888
7 hours ago
$begingroup$
BitNot should yield 221
$endgroup$
– bc888
7 hours ago
6
6
$begingroup$
Integers can have arbitrary length, so how many leading zeros should be flipped? The documentation clarifies: "Integers are assumed to be represented in two's complement form, with an unlimited number of digits, so that
BitNot[n] is simply equivalent to -1-n."$endgroup$
– Chip Hurst
7 hours ago
$begingroup$
Integers can have arbitrary length, so how many leading zeros should be flipped? The documentation clarifies: "Integers are assumed to be represented in two's complement form, with an unlimited number of digits, so that
BitNot[n] is simply equivalent to -1-n."$endgroup$
– Chip Hurst
7 hours ago
|
show 4 more comments
4 Answers
4
active
oldest
votes
2
$begingroup$
I don't think there is a built-in function to generate the two's complement representation. Easy to implement though.
twosComplement[x_, n_] := IntegerDigits[2^x - n, 2, n]
twosComplement[35, 8]
(* 1, 1, 0, 1, 1, 1, 0, 1 *)
answered 7 hours ago
Rohit NamjoshiRohit Namjoshi
1,3061213
$endgroup$
add a comment |
5
$begingroup$
twosComplement[x_, n_] := UnitBox@IntegerDigits[x, 2, n]
twosComplement[35, 8]
1, 1, 0, 1, 1, 1, 0, 1
answered 7 hours ago
Okkes DulgerciOkkes Dulgerci
5,3541918
$endgroup$
add a comment |
2
$begingroup$
FlipBits[num_Integer, len_.] :=
Module[arr, arr = IntegerDigits[num, 2, len];
1 - arr]
answered 7 hours ago
bc888bc888
363
New contributor
bc888 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
1
$begingroup$
Without using IntegerDigits[]:
With[n = 34,
n, BitXor[BitShiftLeft[1, BitLength[n]] - 1, n] // BaseForm[#, 2] &]
100010₂, 11101₂
With[n = 34, p = 8,
n, BitXor[BitShiftLeft[1, p] - 1, n] // BaseForm[#, 2] &]
100010₂, 11011101₂
answered 6 hours ago
J. M. is slightly pensive♦J. M. is slightly pensive
97.8k10304464
$endgroup$
add a comment |
Your Answer
StackExchange.ifUsing("editor", function ()
return StackExchange.using("mathjaxEditing", function ()
StackExchange.MarkdownEditor.creationCallbacks.add(function (editor, postfix)
StackExchange.mathjaxEditing.prepareWmdForMathJax(editor, postfix, [["$", "$"], ["\\(","\\)"]]);
);
);
, "mathjax-editing");
StackExchange.ready(function()
var channelOptions =
tags: "".split(" "),
id: "387"
;
initTagRenderer("".split(" "), "".split(" "), channelOptions);
StackExchange.using("externalEditor", function()
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled)
StackExchange.using("snippets", function()
createEditor();
);
else
createEditor();
);
function createEditor()
StackExchange.prepareEditor(
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: false,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: null,
bindNavPrevention: true,
postfix: "",
imageUploader:
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
,
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
);
);
bc888 is a new contributor. Be nice, and check out our Code of Conduct.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f193136%2fbitnot-does-not-flip-bits-in-the-way-i-expected%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
4 Answers
4
active
oldest
votes
4 Answers
4
active
oldest
votes
active
oldest
votes
active
oldest
votes
2
$begingroup$
I don't think there is a built-in function to generate the two's complement representation. Easy to implement though.
twosComplement[x_, n_] := IntegerDigits[2^x - n, 2, n]
twosComplement[35, 8]
(* 1, 1, 0, 1, 1, 1, 0, 1 *)
answered 7 hours ago
Rohit NamjoshiRohit Namjoshi
1,3061213
$endgroup$
add a comment |
2
$begingroup$
I don't think there is a built-in function to generate the two's complement representation. Easy to implement though.
twosComplement[x_, n_] := IntegerDigits[2^x - n, 2, n]
twosComplement[35, 8]
(* 1, 1, 0, 1, 1, 1, 0, 1 *)
answered 7 hours ago
Rohit NamjoshiRohit Namjoshi
1,3061213
$endgroup$
add a comment |
2
2
2
$begingroup$
I don't think there is a built-in function to generate the two's complement representation. Easy to implement though.
twosComplement[x_, n_] := IntegerDigits[2^x - n, 2, n]
twosComplement[35, 8]
(* 1, 1, 0, 1, 1, 1, 0, 1 *)
answered 7 hours ago
Rohit NamjoshiRohit Namjoshi
1,3061213
$endgroup$
I don't think there is a built-in function to generate the two's complement representation. Easy to implement though.
twosComplement[x_, n_] := IntegerDigits[2^x - n, 2, n]
twosComplement[35, 8]
(* 1, 1, 0, 1, 1, 1, 0, 1 *)
answered 7 hours ago
Rohit NamjoshiRohit Namjoshi
1,3061213
answered 7 hours ago
Rohit NamjoshiRohit Namjoshi
1,3061213
answered 7 hours ago
Rohit NamjoshiRohit Namjoshi
1,3061213
answered 7 hours ago
Rohit NamjoshiRohit Namjoshi
1,3061213
1,3061213
add a comment |
add a comment |
5
$begingroup$
twosComplement[x_, n_] := UnitBox@IntegerDigits[x, 2, n]
twosComplement[35, 8]
1, 1, 0, 1, 1, 1, 0, 1
answered 7 hours ago
Okkes DulgerciOkkes Dulgerci
5,3541918
$endgroup$
add a comment |
5
$begingroup$
twosComplement[x_, n_] := UnitBox@IntegerDigits[x, 2, n]
twosComplement[35, 8]
1, 1, 0, 1, 1, 1, 0, 1
answered 7 hours ago
Okkes DulgerciOkkes Dulgerci
5,3541918
$endgroup$
add a comment |
5
5
5
$begingroup$
twosComplement[x_, n_] := UnitBox@IntegerDigits[x, 2, n]
twosComplement[35, 8]
1, 1, 0, 1, 1, 1, 0, 1
answered 7 hours ago
Okkes DulgerciOkkes Dulgerci
5,3541918
$endgroup$
twosComplement[x_, n_] := UnitBox@IntegerDigits[x, 2, n]
twosComplement[35, 8]
1, 1, 0, 1, 1, 1, 0, 1
answered 7 hours ago
Okkes DulgerciOkkes Dulgerci
5,3541918
answered 7 hours ago
Okkes DulgerciOkkes Dulgerci
5,3541918
answered 7 hours ago
Okkes DulgerciOkkes Dulgerci
5,3541918
answered 7 hours ago
Okkes DulgerciOkkes Dulgerci
5,3541918
5,3541918
add a comment |
add a comment |
2
$begingroup$
FlipBits[num_Integer, len_.] :=
Module[arr, arr = IntegerDigits[num, 2, len];
1 - arr]
answered 7 hours ago
bc888bc888
363
New contributor
bc888 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
2
$begingroup$
FlipBits[num_Integer, len_.] :=
Module[arr, arr = IntegerDigits[num, 2, len];
1 - arr]
answered 7 hours ago
bc888bc888
363
New contributor
bc888 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
add a comment |
2
2
2
$begingroup$
FlipBits[num_Integer, len_.] :=
Module[arr, arr = IntegerDigits[num, 2, len];
1 - arr]
answered 7 hours ago
bc888bc888
363
New contributor
bc888 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
$endgroup$
FlipBits[num_Integer, len_.] :=
Module[arr, arr = IntegerDigits[num, 2, len];
1 - arr]
answered 7 hours ago
bc888bc888
363
New contributor
bc888 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 7 hours ago
bc888bc888
363
New contributor
bc888 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
answered 7 hours ago
bc888bc888
363
answered 7 hours ago
bc888bc888
363
363
New contributor
bc888 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
New contributor
bc888 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
bc888 is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.
add a comment |
add a comment |
1
$begingroup$
Without using IntegerDigits[]:
With[n = 34,
n, BitXor[BitShiftLeft[1, BitLength[n]] - 1, n] // BaseForm[#, 2] &]
100010₂, 11101₂
With[n = 34, p = 8,
n, BitXor[BitShiftLeft[1, p] - 1, n] // BaseForm[#, 2] &]
100010₂, 11011101₂
answered 6 hours ago
J. M. is slightly pensive♦J. M. is slightly pensive
97.8k10304464
$endgroup$
add a comment |
1
$begingroup$
Without using IntegerDigits[]:
With[n = 34,
n, BitXor[BitShiftLeft[1, BitLength[n]] - 1, n] // BaseForm[#, 2] &]
100010₂, 11101₂
With[n = 34, p = 8,
n, BitXor[BitShiftLeft[1, p] - 1, n] // BaseForm[#, 2] &]
100010₂, 11011101₂
answered 6 hours ago
J. M. is slightly pensive♦J. M. is slightly pensive
97.8k10304464
$endgroup$
add a comment |
1
1
1
$begingroup$
Without using IntegerDigits[]:
With[n = 34,
n, BitXor[BitShiftLeft[1, BitLength[n]] - 1, n] // BaseForm[#, 2] &]
100010₂, 11101₂
With[n = 34, p = 8,
n, BitXor[BitShiftLeft[1, p] - 1, n] // BaseForm[#, 2] &]
100010₂, 11011101₂
answered 6 hours ago
J. M. is slightly pensive♦J. M. is slightly pensive
97.8k10304464
$endgroup$
Without using IntegerDigits[]:
With[n = 34,
n, BitXor[BitShiftLeft[1, BitLength[n]] - 1, n] // BaseForm[#, 2] &]
100010₂, 11101₂
With[n = 34, p = 8,
n, BitXor[BitShiftLeft[1, p] - 1, n] // BaseForm[#, 2] &]
100010₂, 11011101₂
answered 6 hours ago
J. M. is slightly pensive♦J. M. is slightly pensive
97.8k10304464
answered 6 hours ago
J. M. is slightly pensive♦J. M. is slightly pensive
97.8k10304464
answered 6 hours ago
J. M. is slightly pensive♦J. M. is slightly pensive
97.8k10304464
answered 6 hours ago
J. M. is slightly pensive♦J. M. is slightly pensive
97.8k10304464
97.8k10304464
add a comment |
add a comment |
bc888 is a new contributor. Be nice, and check out our Code of Conduct.
draft saved
draft discarded
bc888 is a new contributor. Be nice, and check out our Code of Conduct.
bc888 is a new contributor. Be nice, and check out our Code of Conduct.
bc888 is a new contributor. Be nice, and check out our Code of Conduct.
Thanks for contributing an answer to Mathematica Stack Exchange!
- Please be sure to answer the question. Provide details and share your research!
But avoid …
- Asking for help, clarification, or responding to other answers.
- Making statements based on opinion; back them up with references or personal experience.
Use MathJax to format equations. MathJax reference.
To learn more, see our tips on writing great answers.
draft saved
draft discarded
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
StackExchange.ready(
function ()
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fmathematica.stackexchange.com%2fquestions%2f193136%2fbitnot-does-not-flip-bits-in-the-way-i-expected%23new-answer', 'question_page');
);
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Sign up or log in
StackExchange.ready(function ()
StackExchange.helpers.onClickDraftSave('#login-link');
);
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Sign up using Google
Sign up using Facebook
Sign up using Email and Password
Post as a guest
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
Required, but never shown
4
$begingroup$
"IntegerDigits[n] discards the sign of n."
$endgroup$
– kglr
7 hours ago
$begingroup$
Is there a work around?
$endgroup$
– bc888
7 hours ago
$begingroup$
not any I know of.
$endgroup$
– kglr
7 hours ago
$begingroup$
BitNot should yield 221
$endgroup$
– bc888
7 hours ago
6
$begingroup$
Integers can have arbitrary length, so how many leading zeros should be flipped? The documentation clarifies: "Integers are assumed to be represented in two's complement form, with an unlimited number of digits, so that
BitNot[n]is simply equivalent to-1-n."$endgroup$
– Chip Hurst
7 hours ago